Kam*_*icz 1 java mysql hibernate spring-data-jpa
@Entity
@Table(name="student")
public class Student
@Id
private Integer id;
private String name;
private Integer count;
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我想分配给
计数
count = SELECT COUNT(*) FROM people
如何SELECT COUNT(*) FROM people 使用JpaRepository 分配结果:to Integer count?
@Formula帮助您创建自己的公式Hibernate.
@Entity
@Table(name="student")
public class Student
@Id
private Integer id;
private String name;
@Formula("(SELECT COUNT(*) FROM people)") // people is table name not entity
private Integer count;
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