如何导出mapStateToProps和Redux Form？

Question

我正在使用Redux Form(版本6)登录页面.我想要做的是当用户填写表单并单击提交时,从我的状态中获取文本,以便最终可以使用该电子邮件和密码发送操作.但是,在使用react-redux和Redux Form的连接时,我在导出此组件时遇到问题.

使用react-redux时,在将状态映射到props时,想要像这样导出connect:

export default connect(mapStateToProps)(LogInForm)

但是,Redux Form希望它的导出设置如下:

export default reduxForm({
  form: 'LogInForm',
  validate,
})(LogInForm);

有没有办法将这两者结合起来？我尝试过类似的东西:

const reduxFormConfig = reduxForm({
  form: 'LogInForm',
  validate,
});

export default connect(mapStateToProps)(ReduxFormConfig)(LogInForm)

但它不起作用.

或许这是处理这个问题的更好方法？以下是我的组件中的完整代码:

import React from 'react';
import { connect } from 'react-redux';
import { Field, reduxForm } from 'redux-form';
import InputField from '../InputField';
import { validateLogInSignUp as validate } from '../../utils/validateForms.js';

const LogInForm = (props) => {
  const {
    handleSubmit,
    pristine,
    submitting,
  } = props;

  return (
    <div>
      <form onSubmit={handleSubmit}>
        <Field
          name="email"
          type="email"
          component={InputField}
          label="email"
        />
        <Field
          name="password"
          type="password"
          component={InputField}
          label="password"
        />
        <div>
          <button type="submit" disabled={submitting}>Submit</button>
        </div>
      </form>
    </div>
  );
};

const mapStateToProps = state => {
  return {
    loginInput: state.form,
  };
};

// export default connect(mapStateToProps)(LogInForm)

// export default reduxForm({
//  form: 'LogInForm',
//  validate,
// })(LogInForm);

任何和所有的帮助非常感谢.谢谢!

Answer 1

还有一种方法可以将这两个结合在reduxForm v6中:

reduxForm({
  form: 'LogInForm',
  validate,
})(LogInForm);

export default connect(mapStateToProps)(LogInForm)

方法如下:

import React, { Component } from 'react';
import { connect } from 'react-redux

class LogInForm extends Component {
    ...
}

function mapStateToProps(state) {
    return { ... }
}

function mapDispatchToProps(dispatch) {
    return { ... }
}

// First decorate your component with reduxForm
LogInForm = reduxForm({
  form: 'LogInForm',
  validate,
})(LogInForm);

// Then connect the whole with the redux store
export default connect(mapStateToProps, maDispatchToProps)(LogInForm)

Answer 2

使用redux-form您不需要直接访问LoginForm. 相反，您应该在提交表单时访问父组件中的值：

// LoginForm.js
const LogInForm = (props) => {
  ...
};

export default reduxForm({
  form: 'LogInForm',
  validate,
})(LogInForm);


// Parent.js
import LoginForm from './LoginForm';

const handleSubmit = (values) => {
  alert(JSON.stringify(values));  // { email: 'foo@bar.com', password: '1forest1' }
};

const Parent = (props) => {
  return (
    <LoginForm onSubmit={ handleSubmit } />
  );
};

有关简单表单的更完整示例，请参阅https://github.com/erikras/redux-form/blob/master/examples/simple/src/index.js#L42 。