另一个函数内部的 Flask Celery update_state

Question

我想从另一个函数更新我的 Celery 任务的状态。这是我现在所拥有的：

路线

@app.route('/my-long-function', methods=['POST'])
def my_long_function():

    param1 = request.form['param1']
    param2 = request.form['param2']

    task = outside_function.delay(param1, param2)

    return task.id

Celery Task - 在后台启动 some_python_script.handle

@celery.task(name='outside_function')
def outside_function(param1, param2):
    with app.app_context():
        some_python_script.handle(param1, param2)

some_python_script.handle:

def handle(param1, param2):
    param1 + param2
    # many, many different things

理想情况下，我希望能够 self.update_state celery 任务，以便我可以轻松地从我的应用程序请求其状态，如下所示：

some_python_script.handle（理想情况下）：

def handle(param1, param2):
    param1 + param2
    # many, many different things
    self.outside_function.update_state('PROGRESS', meta = {'status':'progressing'})

检查进度（理想情况下）：

@app.route('/status/<task_id>')
def taskstatus(task_id):
    task = outside_function.AsyncResult(task_id)
    response = {
    'state': task.state,
    'id': task.id,
    'status' : task.status,
    }

    return jsonify(response)

或者类似的东西。感谢您的帮助，我对芹菜很陌生！

Answer 1

您应该声明调用的任务ID。您可以检查update_state。

下面的代码应该可以工作。

# capture id of celery task
ID = self.request.id

def handle(param1, param2):
    param1 + param2
    # many, many different things
    # update the state of celery task with direct reference to it
    self.update_state(task_id=ID, state='PROGRESS', meta = {'status':'progressing'})