正如标题所示......当用户单击Java Swing应用程序中的按钮时,我尝试使用以下代码执行PHP脚本:
URL url = new URL( "http://www.mywebsite.com/my_script.php" );
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.connect();
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但没有任何反应...... 有什么不对吗?
我想你错过了下一步,例如:
InputStream is = conn.getInputStream();
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HttpURLConnection基本上只打开套接字connect,以便做一些事情,你需要做一些事情,如打电话getInputStream()或更好getResponseCode()
URL url = new URL( "http://google.com/" );
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
if( conn.getResponseCode() == HttpURLConnection.HTTP_OK ){
InputStream is = conn.getInputStream();
// do something with the data here
}else{
InputStream err = conn.getErrorStream();
// err may have useful information.. but could be null see javadocs for more information
}
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