Tho*_*lik 7 angular2-routing angular2-services angular
我想将逻辑从组件转移到服务.但我发现我无法在服务中获得routeParams.
我的组件看起来像
import { Component, OnInit } from '@angular/core';
import { ActivatedRoute, Params } from '@angular/router';
import { MyService } from '../services/my.service';
@Component({
moduleId: module.id,
templateUrl: 'my.component.html',
styleUrls: ['my.component.css']
})
export class MyComponent implements OnInit {
constructor(private myService: MyService, private route: ActivatedRoute) {;}
public ngOnInit() {
this.route.params
.subscribe((params: Params) => {
debugger;
console.log(params);
});
this.myService.getParams()
.subscribe((params: Params) => {
debugger;
console.log('Return1:');
console.log(params);
}, (params: Params) => {
debugger;
console.log('Return2:');
console.log(params);
}, () => {
debugger;
console.log('Return3:');
});
}
};
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我的服务看起来像
import { Injectable } from '@angular/core';
import { Params, ActivatedRoute } from '@angular/router';
import { Observable } from 'rxjs';
@Injectable()
export class MyService {
constructor(private route: ActivatedRoute) {;}
public getParams(): Observable<Params> {
this.route.params.subscribe((params: Params) => {
debugger;
console.log('Service1:');
console.log(params);
}, (params: Params) => {
debugger;
console.log('Service2:');
console.log(params);
}, () => {
debugger;
console.log('Service3:');
});
return this.route.params;
}
};
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当我调试时,我可以看到params填充组件并且在服务中为空.结果就是这样
Component:
Object {param: "1"}
Service1:
Object {}
Return1:
Object {}
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我正在使用Angular 2.0.0.为什么组件和服务有所不同?是否可以在服务中获得参数?
根据这一点,你必须遍历路由树并从树底部的路线获取数据.
@Injectable()
export class MyService{
constructor(private router:Router,private route:ActivatedRoute){
this.router.events
.filter(event => event instanceof NavigationEnd)
.subscribe((event) => {
let r=this.route;
while (r.firstChild) {
r = r.firstChild
}
//we need to use first, or we will end up having
//an increasing number of subscriptions after each route change.
r.params.first().subscribe(params=>{
// Now you can use the params to do whatever you want
});
});
}
}
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小智 4
我们可以将ActivatedRoute从组件传递给服务。然后订阅服务类中的route.params