如何克隆MobX observable？(编辑保存更改)

Question

我有一个简单的反应表单,以及我的MobX商店中的两个observable:

@observable personalInfo = {
        email: '',
        gender: 1,
        birthDate: null, 
        location: ''
    };
@observable personalInfoInEdit = null;

当加载个人信息的形式时(在ctor中)我在我的商店调用一种方法:

reset_PersonalInfoInEdit() {
        this.personalInfoInEdit = observable(this.personalInfo);
}

它的用量只是重置"编辑中"对象,用原始数据中的数据填充它.如果用户按"保存更改",则"编辑"对象将被复制到原始对象.

用另一个observable调用observable()是否有效？对此有任何副作用？(似乎工作)

如果没有,是否有设计模式可以优雅地处理"编辑"对象的这种情况.

Answer 1

首选模式是使用mobx-utils中的createViewModel实用程序函数.所以你会这样做:

import { createViewModel } from 'mobx-utils'

reset_PersonalInfoInEdit() {
    this.personalInfoInEdit = createViewModel(this.personalInfo);
}

这有一个额外的好处,就是在视图模型上有一些实用功能,可以让你轻松地重置为原始数据或将它们提交给原始模型:

class Todo {
  \@observable title = "Test"
}

const model = new Todo()
const viewModel = createViewModel(model);

autorun(() => console.log(viewModel.model.title, ",", viewModel.title))
// prints "Test, Test"
model.title = "Get coffee"
// prints "Get coffee, Get coffee", viewModel just proxies to model
viewModel.title = "Get tea"
// prints "Get coffee, Get tea", viewModel's title is now dirty, and the local value will be printed
viewModel.submit()
// prints "Get tea, Get tea", changes submitted from the viewModel to the model, viewModel is proxying again
viewModel.title = "Get cookie"
// prints "Get tea, Get cookie" // viewModel has diverged again
viewModel.reset()
// prints "Get tea, Get tea", changes of the viewModel have been abandoned