Python短时间格式

Question

在Python中有一种简单的方法来格式化时间(delta),如下所示:

10:11:12 -> 10:11:12
09:10:11 ->  9:10:11 
00:10:11 ->    10:11
00:09:10 ->     9:10
00:00:10 ->       10 (or maybe as 0:10)
00:00:09 ->        9 (or maybe as 0:09)

即抑制前导零和分隔符(但可能不是在时间增量<1分钟时)

Answer 1

如果你有字符串,你可以lstrip任何前导冒号或0:

In [3]: "00:00:10".lstrip("0:")
Out[3]: '10'

In [4]: "09:10:11".lstrip("0:")
Out[4]: '9:10:11'

In [5]: "10:10:11".lstrip("0:")
Out[5]: '10:10:11'

只要我们有一个0或者,只有当我们找到除了两个字符之外的任何东西时才停止.你可能想要抓住的一个案例是"00:00:00".在那种情况下,我不知道你的期望.

如果你想也右对齐,可以rjust结果:

In [18]: "00:00:19".lstrip("0:").rjust(8)
Out[18]: '      19'

In [19]: "10:00:19".lstrip("0:").rjust(8)
Out[19]: '10:00:19'

In [20]: "09:00:19".lstrip("0:").rjust(8)
Out[20]: ' 9:00:19'

使用str.format作为@ C.LECLERC评论.

"{:>8}".format("00:10:11".lstrip("0:"))

如果你不进入几天,你只需要在timedeltas上调用str:

In [6]: from datetime import timedelta
   ...: 
   ...: td1,td2,td3 = timedelta(hours=10, minutes=10), timedelta(seconds=10),tim
   ...: edelta(minutes=9, seconds=10)
   ...: for t in (td1, td2, td3):
   ...:     print(str(t))
   ...:     print(str(t).lstrip("0:"))
   ...:     
10:10:00
10:10:00
0:00:10
10
0:09:10
9:10

如果要设置最小时间段,即> = 1分钟:

from datetime import timedelta
mn = timedelta(minutes=1)

td1,td2,td3 = timedelta(hours=10, minutes=10), timedelta(seconds=10),timedelta(minutes=9, seconds=10)
for t in (td1, td2, td3):
    if t >= mn:
         print(str(t).lstrip("0:"))
    else:
        print(str(t))