Raf*_*mão 5 wpf viewbox imagesource
我正在使用Viewbox创建一组图标,这些图标将动态绑定到WPF视图。
我将绑定到资源名称,并使用Converter将资源名称转换为ImageSource。
我知道如果资源是a Path时该怎么做,但是如何使用a来做呢Viewbox?
如果资源是Path,这就是我如何将资源名称转换为ImageSource:
public class ResourceNameToImageSourceConverter : BaseValueConverter {
protected override ImageSource Convert(string value, System.Globalization.CultureInfo culture) {
var resource = new ResourceDictionary();
resource.Source = new Uri("pack://application:,,,/MyAssembly;component/MyResourceFolder/ImageResources.xaml", UriKind.Absolute);
var path = resource[value] as Path;
if (path != null) {
var geometry = path.Data;
var geometryDrawing = new GeometryDrawing();
geometryDrawing.Geometry = geometry;
var drawingImage = new DrawingImage(geometryDrawing);
geometryDrawing.Brush = path.Fill;
geometryDrawing.Pen = new Pen();
drawingImage.Freeze();
return drawingImage;
} else {
return null;
}
}
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}
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And this is what the Viewbox declaration looks like.
<Viewbox>
<Viewbox>
<Grid>
<Path>
...
</Path>
<Path>
...
</Path>
<Path>
...
</Path>
<Rectangle>
...
</Rectangle>
</Grid>
</Viewbox>
</Viewbox>
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Viewbox 是一个视觉元素,因此您需要将其手动“渲染”为位图。这篇博文展示了这是如何完成的,但相关代码是:
private static BitmapSource CaptureScreen(Visual target, double dpiX, double dpiY) {
if (target == null)
return null;
Rect bounds = VisualTreeHelper.GetDescendantBounds(target);
RenderTargetBitmap rtb = new RenderTargetBitmap((int)(bounds.Width * dpiX / 96.0),
(int)(bounds.Height * dpiY / 96.0),
dpiX,
dpiY,
PixelFormats.Pbgra32);
DrawingVisual dv = new DrawingVisual();
using (DrawingContext ctx = dv.RenderOpen()) {
VisualBrush vb = new VisualBrush(target);
ctx.DrawRectangle(vb, null, new Rect(new Point(), bounds.Size));
}
rtb.Render(dv);
return rtb;
}
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