在python中的两个之间将更快和更有利
a = b = c = d = 1
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和
a = 1
b = 1
c = 1
d = 1
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只需运行测试:
>>> import timeit
>>> min(timeit.repeat('a = b = c = d = 1', number=10000000))
0.4885740280151367
>>> min(timeit.repeat('a = 1; b = 1; c = 1; d = 1', number=10000000))
0.6283371448516846
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另请注意:
>>> min(timeit.repeat('a, b, c, d = 1, 1, 1, 1', number=10000000))
0.4040501117706299
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