Symfony2从事件侦听器重定向到URL

Question

当symfony抛出异常时,我需要从EventListener重定向到自定义URL

在我的service.yml

app.exception_listener:
    class: AppBundle\EventListener\ExceptionListener
    tags:
        - { name: kernel.event_listener, event: kernel.exception, method: onKernelException  }

在我的PHP课程中

<?php

namespace AppBundle\EventListener;

use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpKernel\Exception\HttpExceptionInterface;
use Symfony\Component\DependencyInjection\Container;
use Symfony\Component\HttpFoundation\RedirectResponse;

class ExceptionListener {

public function onKernelException(GetResponseForExceptionEvent $event) {
    // You get the exception object from the received event
    $exception = $event->getException();

    if ($exception instanceof NotFoundHttpException) {

        //i need this function
        return $this->redirect('https://www.google.co.ve/?gws_rd=ssl', 404);
    }
}

}

Answer 1

代替:

return $ this-> redirect(' https://www.google.co.ve/?gws_rd=ssl',404);

做:

$ event-> setResponse(new RedirectResponse(' https://www.google.co.ve/?gws_rd=ssl '));

另请注意,发送带有404响应的Location标头并不合理,您应该使用3xx范围内的响应.在尝试使用其他状态代码重定向时,Symfony实际上(正确地)会抛出异常.