我正在从"Pragmatic Bookshelf Programming Scala"一书中做所有的例子.这是一个简单的单例示例,但我没有把它弄好,即不提取map中的值.你能指出错误吗?
class Marker(val color: String) {
println("Creating " + this)
override def toString(): String = "marker color is " + color
}
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而单身MarkerFactory如下
object MarkerFactory {
private val markers = new HashMap[String, Marker];
markers += "red" -> new Marker("red")
markers += "blue" -> new Marker("blue")
markers += "green" -> new Marker("green")
def getMarker(color: String) {
if (markers.contains(color)) markers(color) else null
}
def main(args: Array[String]) {
println(markers)
println((MarkerFactory getMarker "red").toString)
println(MarkerFactory getMarker "blue")
println(MarkerFactory getMarker "red")
println(MarkerFactory getMarker "yellow")
}
}
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我得到这样的输出.
Creating marker color is red
Creating marker color is blue
Creating marker color is green
Map(green -> marker color is green, red -> marker color is red, blue -> marker color is blue)
()
()
()
()
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Ken*_*oom 10
使用没有等号的开放式大括号对于返回的方法来说是神秘的简写Unit.(()是a的唯一有效值Unit,这就是您的代码打印的原因().)
def getMarker(color: String) {
if (markers.contains(color)) markers(color) else null
}
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将其更改为
def getMarker(color: String) = {
if (markers.contains(color)) markers(color) else null
}
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或者更好
def getMarker(color: String) = markers.getOrElse(color,null)
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