开关盒组装语言

Cat*_*tie 8 x86 assembly disassembly switch-statement

我正在查看switch语句的汇编语言代码.

我理解代码如何工作以及案例是什么.我的问题是我如何决定案件名称?

下面是汇编语言代码,我将对其进行解释.我基本上只需要使用跳转表并填写案例名称.

    1 8048420: push %ebp
    2 8048421: mov %esp, $ebp
    3 8048423: mov 0x8(%ebp), %eax       // x
    4 8048426: mov 0xc(%ebp), %edx       // n
    5 8048429: sub $0x32, %edx           // so least value of case is 32
    6 804842c: cmp $0x5, %edx            // max value is 37
    7 804842f: ja 8048448 <switch+0x28>  // if >37, go to default
    8 8048431: jmp *0x80485d0(, %edx, 4)  //THIS RIGHT HERE ?
    9 8048438: shl $0x2, %eax             // CASE A
   10 804843b: jmp 804844b <switch+0x2b>  //break;
   11 804843d: sar $0x2, %eax             //CASE B
   12 8048440: jmp 804844b <switch+0x2b>  //break
   13 8048442: lea (%eax, %eax, 2), %eax  //CASE C
   14 8048445: imul %eax, %eax     
   15 8048448: add $0xa, %eax             //fall through to default
   16 804844b: pop %ebp                   //return
   17 804844c: ret
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gdb命令创建的跳转表:我正在做x/6w 0x80485d0

0x80485d0: 0x08048438 0x08048448 0x08048438 0x0804843d
0x80485e0: 0x08048442 0x08048445
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我的解释:

int result = x;
switch(n) {
case __:
    x = x << 2;
    break;  
case __:
    x = x >> 2
    break;
case __:
    x = 4*x;
    x = x*x
case __: //default
    x += 0xa 
return x;
}
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我只是不明白如何查找跳转表并确定32到37之间的n值适合哪种情况下的空白.

任何帮助,将不胜感激.谢谢.

out*_*tis 6

正如奥利所说,没有更多的事要做.n-50存储在%edx中,然后切换+ 0x11跳转到存储的地址0x80485d0 + %edx * 4.看一下表,当n == 50或52时,开关+ 0x18,当n == 51时切换+ 0x28,当n == 53时切换+ 0x1d,当n == 54时切换+ 0x22,当n =时切换+ 0x25 = 55.