与Jest嘲笑承诺的基本要求

Question

我正在尝试使用Jest对一个函数进行单元测试,并且我在处理jest模拟模块时遇到了一些麻烦(相当于nodejs世界中的重新连接或代理查询).

我实际上试图测试一个间谍已经被模拟模块调用了一些参数.这是我想要测试的功能.

注意:当前测试仅涉及"fetch(...)"部分,我试图测试已使用good参数调用fetch.

export const fetchRemote = slug => {
    return dispatch => {
        dispatch(loading());
        return fetch(Constants.URL + slug)
            .then(res => res.json())
            .then(cmp => {
                if (cmp.length === 1) {
                    return dispatch(setCurrent(cmp[0]));
                }
                return dispatch(computeRemote(cmp));
            });
    };
};

返回的函数充当闭包,因此"捕获"我想要模拟的节点获取外部模块.

这是我试图通过绿色的测试:

it('should have called the fetch function wih the good const parameter and slug', done => {
            const slug = 'slug';
            const spy = jasmine.createSpy();
            const stubDispatch = () => Promise.resolve({json: () => []});
            jest.mock('node-fetch', () => spy);
            const dispatcher = fetchRemote(slug);
            dispatcher(stubDispatch).then(() => {
                expect(spy).toHaveBeenCalledWith(Constants.URL + slug);
                done();
            });
        });

编辑:第一个答案有助于编写测试,我现在有以下一个:

it('should have called the fetch function wih the good const parameter and slug', done => {
            const slug = 'slug';
            const stubDispatch = () => null;
            const spy = jest.mock('node-fetch', () => Promise.resolve({json: () => []}));
            const dispatcher = fetchRemote(slug);
            dispatcher(stubDispatch).then(() => {
                expect(spy).toHaveBeenCalledWith(Constants.URL + slug);
                done();
            });
        });

但现在,这是我的错误:

 console.error node_modules/core-js/modules/es6.promise.js:117
      Unhandled promise rejection [Error: expect(jest.fn())[.not].toHaveBeenCalledWith()

      jest.fn() value must be a mock function or spy.
      Received:
        object: {"addMatchers": [Function anonymous], "autoMockOff": [Function anonymous], "autoMockOn": [Function anonymous], "clearAllMocks": [Function anonymous], "clearAllTimers": [Function anonymous], "deepUnmock": [Function anonymous], "disableAutomock": [Function anonymous], "doMock": [Function anonymous], "dontMock": [Function anonymous], "enableAutomock": [Function anonymous], "fn": [Function anonymous], "genMockFn": [Function bound getMockFunction], "genMockFromModule": [Function anonymous], "genMockFunction": [Function bound getMockFunction], "isMockFunction": [Function isMockFunction], "mock": [Function anonymous], "resetModuleRegistry": [Function anonymous], "resetModules": [Function anonymous], "runAllImmediates": [Function anonymous], "runAllTicks": [Function anonymous], "runAllTimers": [Function anonymous], "runOnlyPendingTimers": [Function anonymous], "runTimersToTime": [Function anonymous], "setMock": [Function anonymous], "unmock": [Function anonymous], "useFakeTimers": [Function anonymous], "useRealTimers": [Function anonymous]}]

Answer 1

首先,在测试异步代码时需要返回一个promise .而你的间谍需要回复已解决或被拒绝的承诺.

it('should have called the fetch function wih the good const parameter and slug', done => {
  const slug = 'successPath';
  const stubDispatch = () => Promise.resolve({ json: () => [] });
  spy = jest.mock('node-fetch', (path) => {
    if (path === Constants.URL + 'successPath') {
      return Promise.resolve('someSuccessData ')
    } else {
      return Promise.reject('someErrorData')
    }
  });
  const dispatcher = fetchRemote(slug);
  return dispatcher(stubDispatch).then(() => {
    expect(spy).toHaveBeenCalledWith(Constants.URL + slug);
    done();
  });
});