Pra*_*har 3 laravel laravel-5 laravel-facade
在用户的编辑个人资料页面上,我想显示当前登录用户详细信息的现有值,如姓名,电子邮件,性别等.我的问题如下
$user = Auth::user();在我的控制器中创建一个变量,并将其传递给我的视图,就像常规对象一样?每次使用时,在给定视图文件上多次使用Auth :: user()都会命中我的数据库吗?
提前致谢.
小智 8
如果查看该SessionGuard.php文件Illuminate\Auth,您将看到user()用于检索当前已验证用户的方法:
/**
* Get the currently authenticated user.
*
* @return \Illuminate\Contracts\Auth\Authenticatable|null
*/
public function user()
{
if ($this->loggedOut) {
return;
}
// If we've already retrieved the user for the current request we can just
// return it back immediately. We do not want to fetch the user data on
// every call to this method because that would be tremendously slow.
if (! is_null($this->user)) {
return $this->user;
}
$id = $this->session->get($this->getName());
// First we will try to load the user using the identifier in the session if
// one exists. Otherwise we will check for a "remember me" cookie in this
// request, and if one exists, attempt to retrieve the user using that.
$user = null;
if (! is_null($id)) {
if ($user = $this->provider->retrieveById($id)) {
$this->fireAuthenticatedEvent($user);
}
}
// If the user is null, but we decrypt a "recaller" cookie we can attempt to
// pull the user data on that cookie which serves as a remember cookie on
// the application. Once we have a user we can return it to the caller.
$recaller = $this->getRecaller();
if (is_null($user) && ! is_null($recaller)) {
$user = $this->getUserByRecaller($recaller);
if ($user) {
$this->updateSession($user->getAuthIdentifier());
$this->fireLoginEvent($user, true);
}
}
return $this->user = $user;
}
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//如果我们已经为当前请求检索了用户,我们可以立即将其返回.我们不想在每次调用此方法时获取用户数据,因为这将非常慢.
if (! is_null($this->user)) {
return $this->user;
}
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因此,user()多次调用不会对数据库进行多次调用.
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