如何按标签过滤docker swarm节点?

Nat*_*eid 5 docker docker-swarm

我正在运行docker 1.12.1,无法通过标签进行节点过滤工作。我首先添加“测试”标签:

$ docker node update --label-add test mr-host
mr-host
Run Code Online (Sandbox Code Playgroud)

当我尝试按其筛选时,未显示任何节点:

$ docker node ls --filter label=test
ID  HOSTNAME  STATUS  AVAILABILITY  MANAGER STATUS
Run Code Online (Sandbox Code Playgroud)

通过其他条件(例如名称)进行过滤可以正常工作:

$ docker node ls --filter name=mr-host
ID                           HOSTNAME  STATUS  AVAILABILITY  MANAGER STATUS
1c48m4msidbqwx7vj0lwib8ef *  mr-host   Ready   Active        Leader
Run Code Online (Sandbox Code Playgroud)

当我检查节点时,将显示标签:

$ docker node inspect mr-host
[
    {
        "ID": "1c48m4msidbqwx7vj0lwib8ef",
        "Version": {
            "Index": 4865874
        },
        "CreatedAt": "2016-10-12T15:20:10.463286132Z",
        "UpdatedAt": "2016-10-13T16:29:03.113522485Z",
        "Spec": {
            "Labels": {
                "test": ""
            },
            "Role": "manager",
            "Availability": "active"
        },
        "Description": {
            "Hostname": "mr-host",
            "Platform": {
                "Architecture": "x86_64",
                "OS": "linux"
            },
            "Resources": {
                "NanoCPUs": 10000000000,
                "MemoryBytes": 67548012544
            },
            "Engine": {
                "EngineVersion": "1.12.1",
                "Plugins": [
                    {
                        "Type": "Network",
                        "Name": "bridge"
                    },
                    {
                        "Type": "Network",
                        "Name": "host"
                    },
                    {
                        "Type": "Network",
                        "Name": "null"
                    },
                    {
                        "Type": "Network",
                        "Name": "overlay"
                    },
                    {
                        "Type": "Volume",
                        "Name": "local"
                    }
                ]
            }
        },
        "Status": {
            "State": "ready"
        },
        "ManagerStatus": {
            "Leader": true,
            "Reachability": "reachable",
            "Addr": "192.168.0.118:2377"
        }
    }
]
Run Code Online (Sandbox Code Playgroud)

我究竟做错了什么?我敢肯定我正确地遵循了这里的文档:https : //docs.docker.com/engine/reference/commandline/node_ls/#/id

BMi*_*tch 2

正如我相信您已经看到的(基于收到的赞),这是docker swarm 的一个已知问题 (#27231) 。