Fra*_*eil 11 sql postgresql datetime-generation
我想生成一个日期列表,希望加入另一个表,但我不知道使用什么语法,类似于这个:
SELECT dates.date, transactions.account_id, transactions.amount
FROM (...) as dates
LEFT JOIN transactions ON transactions.date = dates.date
WHERE dates.date >= '2010-01-01' AND dates.date <= '2010-12-31'
ORDER BY dates.date;
Run Code Online (Sandbox Code Playgroud)
我想要日期,所以我没有必要进一步按摩数据客户端.我用它来显示一个类似于这样的表:
Account 2010-01-01 2010-01-02 2010-01-03 Balance
============================================================
Chase 123 +100 -20 -70 +10
Chase 231 +13 -9 +4
Run Code Online (Sandbox Code Playgroud)
OMG*_*ies 11
使用generate_series函数获取可添加到日期的数字列表,以获取日期列表:
SELECT CURRENT_DATE + s.a AS dates
FROM generate_series(0,14,7) as s(a);
Run Code Online (Sandbox Code Playgroud)
结果:
dates
------------
2004-02-05
2004-02-12
2004-02-19
Run Code Online (Sandbox Code Playgroud)
问题的后半部分涉及转动结果集 - 将行数据转换为柱状数据.PIVOT和UNPIVOT是ANSI,但我认为目前PostgreSQL不支持它们.旋转查询的最一致支持方法是使用聚合函数:
SELECT t.account,
SUM(CASE WHEN t.date = '2010-01-01' THEN t.amount END) AS '2010-01-01',
SUM(CASE WHEN t.date = '2010-01-02' THEN t.amount END) AS '2010-01-02',
SUM(CASE WHEN t.date = '2010-01-03' THEN t.amount END) AS '2010-01-03',
SUM(t.amount) AS Balance
FROM (SELECT CURRENT_DATE + s.a AS dates
FROM generate_series(0,14,7) as s(a)) x
LEFT JOIN TRANSACTIONS y ON y.date = x.date
GROUP BY t.account
Run Code Online (Sandbox Code Playgroud)
...表示动态SQL.