对于每个模板类型,设置类型的参数

Question

假设我有一个可变参数模板类.如何创建一个函数,使其参数属于集合类型,例如int,参数的数量等于模板类型的数量？

template <typename... Types>
class Test
{
public:
    void Func(???); // I don't know how to declare such a function
}

Test<string, bool, long> myTest; // Three types
myTest.Func(905, 36, 123315); // Three arguments, but always of type int.

最后,该函数的目标是返回所提供的int的元组.为简单起见,我在示例代码中将函数显示为void.

Answer 1

template <typename... Types>
class Test
{
    template <typename>
    using int_t = int;

public:    
    void Func(int_t<Types>... ints)
    {
    }
};

DEMO