org.json.JSONException：价格没有价值

Question

我得到结果json并在android中解析。消息发生了异常：org.json.JSONException：价格没有值

W/System.err: org.json.JSONException: No value for price
W/System.err:     at org.json.JSONObject.get(JSONObject.java:389)
W/System.err:     at org.json.JSONObject.getString(JSONObject.java:550)

我的java课

JSONParser jsonParser = new JSONParser();

// tracks JSONArray
JSONArray albums = null;

// Album id
String album_id = null;
String song_id = null;

String album_name, song_name, price;

// single song JSON url
// GET parameters album, song
private static final String URL_SONG = "my url";


// ALL JSON node names
private static final String TAG_NAME = "name";
private static final String TAG_PRICE = "price";
private static final String TAG_ALBUM = "name";     // album
...
try {
       JSONObject jObj = new JSONObject(json);
       if(jObj != null){
            song_name = jObj.getString(TAG_NAME);
            album_name = jObj.getString(TAG_ALBUM);
            price = jObj.getString(TAG_PRICE);
       }
 } 
 catch (JSONException e) {
        e.printStackTrace();
 }

我的json网址：

{
  "id": "551"
  "name": "Rent Disk"
  "price": "3233333"
  "album_id": "3"
  "album": "Michael"
}

如何解决此异常？非常感谢 ！！

Answer 1

您可以在存入价值之前先进行这样的检查

JSONObject jObj = new JSONObject(json);
if(jObj != null) {
    if(jObj.has(TAG_NAME)) {
        song_name = jObj.getString(TAG_NAME);
    }
    if(jObj.has(TAG_ALBUM)){
        album_name = jObj.getString(TAG_ALBUM);
    }
    if(jObj.has(TAG_PRICE)){
        price = jObj.getString(TAG_PRICE);
    }
}