R 创建范围因子水平

Question

我想自动化以下过程：

从向量中获取最小值和最大值，并在给定特定步长的情况下定义从最小值到最大值的步长。向量中的每个值现在都被分配给一个label（因子级别），它落入这个范围，例如"20-30"当值为 时27.45。

目前我正在使用这个 for 循环

for (label_willi_counter in 1:length(willi)) {
  if(willi[label_willi_counter] < 10)
    label_willi = c(label_willi, "0 - 10")
  else if(willi[label_willi_counter] < 20)
    label_willi = c(label_willi, "10 - 20")
  else if(willi[label_willi_counter] < 30)
    label_willi = c(label_willi, "50 - 30")
  else if(willi[label_willi_counter] < 40)
    label_willi = c(label_willi, "30 - 40")
  else if(willi[label_willi_counter] < 50)
    label_willi = c(label_willi, "40 - 50")
  else if(willi[label_willi_counter] < 60)
    label_willi = c(label_willi, "50 - 60")
  else if(willi[label_willi_counter] < 70)
    label_willi = c(label_willi, "60 - 70")
  else if(willi[label_willi_counter] < 80)
    label_willi = c(label_willi, "70 - 80")
  else if(willi[label_willi_counter] < 90)
    label_willi = c(label_willi, "80 - 90")
  else
    label_willi = c(label_willi, "90 - 100")
}

嗯，它正在工作，但我确信有一种更好（并且可能更快）的方法来做到这一点。此示例针对minimum = 0andmaximum = 100和是固定的step-size = 10。我正在寻找一种更通用的方法来做到这一点。

Answer 1

尝试cut：

x
# [1] 60 35 21 30  6 19 49 17 59 93  9 96 46 63  3 58 13 86 47 16

cut(x, breaks = seq(0,100,10), labels = lbl)

#[1] 50-60  30-40  20-30  20-30  0-10   10-20  40-50  10-20  50-60  90-100 0-10   #90-100 40-50  60-70 
#[15] 0-10   50-60  10-20  80-90  40-50  10-20 
#Levels: 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100

数据

x <- c(60L, 35L, 21L, 30L, 6L, 19L, 49L, 17L, 59L, 93L, 9L, 96L, 46L, 
63L, 3L, 58L, 13L, 86L, 47L, 16L)

lbl <- c("0-10", "10-20", "20-30", "30-40", "40-50", "50-60", "60-70", 
"70-80", "80-90", "90-100")