在一个查询中通过计数和运算符获取结果

Question

我认为问题是错误的,但我不知道如何正确提问.

此查询选择job_types包含所有包含其C字母的所有工作者的所有业务.

$connect = DB::table('relationship')
->join('workers', 'workers.id', '=', 'relationship.w_id')
->join('business', 'business.id', '=', 'relationship.b_id')
->whereRaw('job_types LIKE "%C%"')
->groupBy('relationship.w_id')
->get();

我正在使用foreach来显示结果

foreach ($connect as $item) {
 echo $item->name;
 // etc
}

我想选择所有超过3或小于3或等于3(取决于我需要的)的job_types LIKE "%C%"商家并存储这样的信息:

1. APPLE | Tom | C
2. APPLE | Tim | C
3. APPLE | Jeff | C
4. IBM | Jenny | C
5. IBM | Sean | C
6. IBM | Ian | C
// etc``

回答@KikiTheOne有点工作,但它不会根据需要显示结果.

Answer 1

*****解决方案*****

SELECT 
 * 
FROM 
    people_details as t1 
inner join 
    people_branches as t2 
on t1.id = t2.id 
    inner join 
    ( 
        SELECT 
            count(t1.id) as worker_counter,t1.branch_id
        FROM 
            people_branches as t1 
                inner join people_details as t2 
                    on t1.id = t2.id 
        WHERE 
            t2.job_types LIKE '%C%' 
            group by branch_id 
    ) as t3 
    on t2.branch_id = t3.branch_id 
inner join people_frontpage as t4 
    on t4.id = t1.id 
inner join business as t5 
    on t5.id = t2.branch_id 
WHERE 
    t1.job_types LIKE '%C%' 
    AND t3.worker_counter > 200

----------

旧 - 更新

1. 
2. 
3. 
4. 

SELECT 
    t3.bus_name, t1.name, t1.job_types 
FROM 
    SO_WORKER as t1 
    inner join 
        SO_RELATIONSHIP as t2 
            on t1.id = t2.w_id 
    inner join 
    (
        SELECT 
            count(t1.w_id) as worker_counter,t1.b_id,t3.bus_name 
        FROM 
            SO_RELATIONSHIP as t1 
            inner join SO_WORKER as t2 
                on t1.w_id = t2.id 
            inner join SO_BUSINESS as t3 
                on t3.id = t1.b_id 
        WHERE 
            t2.job_types LIKE '%C%' 
            group by b_id
    ) as t3 
    on t2.b_id = t3.b_id 
WHERE t1.job_types LIKE '%C%'
AND t3.worker_counter <= 3

未格式化

SELECT t3.bus_name, t1.name, t1.job_types FROM SO_WORKER as t1 inner join SO_RELATIONSHIP as t2 on t1.id = t2.w_id inner join (SELECT count(t1.w_id) as worker_counter,t1.b_id,t3.bus_name FROM SO_RELATIONSHIP as t1 inner join SO_WORKER as t2 on t1.w_id = t2.id inner join SO_BUSINESS as t3 on t3.id = t1.b_id WHERE t2.job_types LIKE '%C%' group by b_id) as t3 on t2.b_id = t3.b_id WHERE t1.job_types LIKE '%C%' AND t3.worker_counter <= 3

--------------------------------------------------

旧代码

关于帖子 1 的评论。

Table: SO_BUSINESS
    id      |       bus_name
    --------------------
    1       |       BUSI A
    2       |       BUSI B

Table: SO_WORKER
    id      |       job_types
    ---------------------
    1       |       CEO
    2       |       GFO
    3       |       CTO
    4       |       Manager
    5       |       Worker

Table: SO_RELATIONSHIP
    w_id    |       b_id
    ----------------
    1       |       1
    2       |       2
    3       |       1
    4       |       1
    5       |       2

Query: Output
    workers_count   |       b_id        |       bus_name
    --------------------------------------------
    2               |       1           |       BUSI A

。

SELECT * 
FROM 
    (
        SELECT 
            count(t1.w_id) as workers_count,
            t1.b_id,
            t3.bus_name
        FROM 
            SO_RELATIONSHIP as t1 
            inner join 
                SO_WORKER as t2 on t1.w_id = t2.id 
            inner join 
                SO_BUSINESS as t3 on t1.b_id = t3.id 
        WHERE 
            t2.job_types LIKE '%C%' 
        GROUP BY t1.b_id
    ) as t4 
WHERE 
    t4.workers_count < 3  

代码未格式化：

SELECT * FROM (SELECT count(t1.w_id) as workers_count,t1.b_id,t3.bus_name FROM SO_RELATIONSHIP as t1 inner join SO_WORKER as t2 on t1.w_id = t2.id inner join SO_BUSINESS as t3 on t1.b_id = t3.id WHERE t2.job_types LIKE '%C%' GROUP BY t1.b_id) as t4 WHERE t4.workers_count < 3  

让我知道这是否对你有帮助