TYPO3 Extbase:如何获取禁用相关的Object,没有原始的sql-query?

Alj*_*cha 5 typo3 extbase

场景:

我有以下型号: 域的模型

ContactPerson与FrontendUser有关系,是关系的拥有方.现在我有以下问题:
我正在激活/停用任务中的FrontendUsers,基于活动的ContactPersons.禁用或删除FrontendUser时,contactPerson-> getFrontendUser()的结果为null,即使两个存储库都是ignoreEnableFields:

    /** @var Typo3QuerySettings $querySettings */
    $querySettings = $this->objectManager->get(Typo3QuerySettings::class);
    $querySettings->setIgnoreEnableFields(true);
    $querySettings->setRespectStoragePage(false);
    $this->frontendUserRepository->setDefaultQuerySettings($querySettings);

    $debugContactPerson = $this->contactPersonRepository->findOneByContactPersonIdAndIncludeDeletedAndHidden('634');
    $debugFrontendUser = $this->frontendUserRepository->findOneByUid(7);
    \TYPO3\CMS\Extbase\Utility\DebuggerUtility::var_dump(
        array(
            '$debugContactPerson' => $debugContactPerson,
            '$debugFrontendUser' => $debugFrontendUser,
        )
    );
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结果: DebugResult

Ps:$this->frontendUserRepository->findByUid(7);也不起作用,因为它没有使用查询,但persistenceManager->getObjectByIdentifier(...当然忽略了查询设置.

问题是,在我的实际代码中我不能使用findOneByUid(),因为我无法在contact_person的frontend_user字段中获取整数值(uid).

没有使用原始查询来获取contact_person-row的任何方法来解决这个问题?


我的(是原始查询)解决方案:

因为我不想编写自己的QueryFactory而且我不想在我的contactPerson中添加冗余字段,所以我现在用原始语句解决了它.也许它可以帮助有同样问题的人:

class FrontendUserRepository extends \TYPO3\CMS\Extbase\Domain\Repository\FrontendUserRepository
{
    /**
     * @param \Vendor\ExtKey\Domain\Model\ContactPerson $contactPerson
     * @return Object
     */
    public function findByContactPersonByRawQuery(ContactPerson $contactPerson){
        $query = $this->createQuery();

        $query->statement(
            "SELECT fe_users.* FROM fe_users" .
            " LEFT JOIN tx_extkey_domain_model_contactperson contact_person ON contact_person.frontend_user = fe_users.uid" .
            " WHERE contact_person.uid = " . $contactPerson->getUid()
        );
        return $query->execute()->getFirst();
    }

}
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Oli*_*der 7

直接调用存储库

表的启用字段有两个方面fe_users:

  • $querySettings->setIgnoreEnableFields(true);
  • $querySettings->setEnableFieldsToBeIgnored(['disable']);

看看维基页面中的一些概述 - 它说6.2,但它在7.6和8的大多数部分仍然有效.但是,这仅在直接调用存储库时有效,但如果将实体作为另一个实体的一部分进行检索则不行 - 在这种情况下,存储库不用于嵌套实体.

修改嵌套实体的查询设置

隐式检索嵌套实体 - 这发生在DataMapper::getPreparedQuery(DomainObjectInterface $parentObject, $propertyName).要调整子实体的查询设置,QueryFactoryInterface必须重载实现.

注册替代实现ext_localconf.php(替换\Vendor\ExtensionName\Persistence\Generic\QueryFactory为扩展的真实类名称):

$extbaseObjectContainer = \TYPO3\CMS\Core\Utility\GeneralUtility::makeInstance(
    \TYPO3\CMS\Extbase\Object\Container\Container::class
);
$extbaseObjectContainer->registerImplementation(
    \TYPO3\CMS\Extbase\Persistence\Generic\QueryFactoryInterface::class,
    \Vendor\ExtensionName\Persistence\Generic\QueryFactory::class
);
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然后在实现中:

<?php
namespace \Vendor\ExtensionName\Persistence\Generic;
use TYPO3\CMS\Extbase\Domain\Model\FrontendUser;

class QueryFactory extends \TYPO3\CMS\Extbase\Persistence\Generic\QueryFactory
{
    public function create($className)
    {
        $query = parent::create($className);
        if (is_a($className, FrontendUser::class, true)) {
            // @todo Find a way to configure that more generic
            $querySettings = $query->getQuerySettings();
            $querySettings->setIgnoreEnableFields(true);
            // ... whatever you need to adjust in addition ...
        }
        return $query;
    }
}
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