rob*_*ams 0 python ipython python-2.7 python-3.x
我想创建一个由前12个乘法表组成的矩阵。
到目前为止,我的代码是:
x = range(1,13,1)
n = range(1,13,1)
list_to_append = []
list_for_matrix = []
for i in x:
for j in n:
list_to_append.append(i*j)
list_for_matrix.append(list_to_append[0:12])
list_for_matrix.append(list_to_append[12:24])
list_for_matrix.append(list_to_append[24:36])
print (list_to_append)
print (list_for_matrix)
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我得到的输出是:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121, 132, 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144]
[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], [2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24], [3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36]]
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在我的for循环中,当i=1和时j = range(1,12,1),我希望输出(i*j)像这样的列表,[1,2,3,4,5,6,7,8,9,10,11,12]并且每次迭代都应该发生这种情况。最后,我想将上面的列表附加到[[1,2,3,4,5,6,7,8,9,,10,11,12]].so 这样的空列表中
,在我的代码中,我无法对12个乘法表进行切片。有什么更好的办法吗?
您可以使用以下列表理解:
x = range(1,13) # default step value is 1, no need to specify
n = range(1,13)
mult_table = [[i*j for j in x] for i in n]
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输出:
print(mult_table)
# [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
# [2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24],
# [3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36],
# [4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48],
# [5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60],
# [6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72],
# [7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84],
# [8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96],
# [9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108],
# [10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120],
# [11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121, 132],
# [12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144]]
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注意嵌套的理解,从中生成另一个维度的值,并与第一个维度的值相乘。
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