Koa*_*la3 77 scala add put mutable map
将元素添加到scala.collection.mutable.Map的语法是什么?
以下是一些失败的尝试:
val map = scala.collection.mutable.Map
map("mykey") = "myval"
map += "mykey" -> "myval"
map.put("mykey","myval")
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Eas*_*sun 85
关键是您的代码的第一行不是您所期望的.你应该用
val map = scala.collection.mutable.Map[A,B]()
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要么
scala> val map = scala.collection.mutable.Map[String,String]()
map: scala.collection.mutable.Map[String,String] = Map()
scala> map("k1") = "v1"
scala> map
res1: scala.collection.mutable.Map[String,String] = Map((k1,v1))
scala> map += "k2" -> "v2"
res2: map.type = Map((k1,v1), (k2,v2))
scala> map.put("k3", "v3")
res3: Option[String] = None
scala> map
res4: scala.collection.mutable.Map[String,String] = Map((k3,v3), (k1,v1), (k2,v2))
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代替.
scala> map.addOne("k4" -> "v4")
res5: map.type = HashMap(k1 -> v1, k2 -> v2, k3 -> v3, k4 -> v4)
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Kev*_*ght 45
一如既往,你应该质疑你是否真的需要一个可变的地图.
构建不可变的地图是微不足道的:
val map = Map(
"mykey" -> "myval",
"myotherkey" -> "otherval"
)
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首次构建时,可变映射没有区别:
val map = collection.mutable.Map(
"mykey" -> "myval",
"myotherkey" -> "otherval"
)
map += "nextkey" -> "nextval"
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在这两种情况下,推理都将用于确定Map实例的正确类型参数.
您还可以在a中保存不可变映射,var然后每次执行"更新"时,都会使用新的不可变映射实例更新变量
var map = Map(
"mykey" -> "myval",
"myotherkey" -> "otherval"
)
map += "nextkey" -> "nextval"
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如果您没有任何初始值,则可以使用Map.empty:
val map : Map[String, String] = Map.empty //immutable
val map = Map.empty[String,String] //immutable
val map = collection.mutable.Map.empty[String,String] //mutable
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Syn*_*sso 18
当你说
val map = scala.collection.mutable.Map
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您不是在创建地图实例,而是使用Map类型别名.
map: collection.mutable.Map.type = scala.collection.mutable.Map$@fae93e
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请尝试以下方法:
scala> val map = scala.collection.mutable.Map[String, Int]()
map: scala.collection.mutable.Map[String,Int] = Map()
scala> map("asdf") = 9
scala> map
res6: scala.collection.mutable.Map[String,Int] = Map((asdf,9))
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