Spr*_*and 11 text text-processing r
我想做一个格式化用于邮寄地址的列,我不能获取换行符/返回载体或<br/>
在制作新列时工作.
name = c("John Smith", "Patty Smith", "Sam Smith")
address = c("111 Main St.", "222 Main St.", "555 C Street")
cityState = c("Portland, OR 97212", "Portland, OR 95212", "Portland, OR 99212")
df <- data.frame(name, address, cityState)
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我想创建一个格式化地址标签中数据的列:John Smith 111 Main st.波特兰,OR 97212
每个新列:每行后都会有一个返回:所以它总是3行.其他3列中的每一列都有一行.
# example of what I am trying to do...
paste0(name, "return", address, "return", cityState). Everything I have tried does not work for making a newline.
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csg*_*pie 11
要获得我们使用的新行(或返回)\n
.所以
addr = paste(name, address, cityState, sep="\n")
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要查看结果,请使用 cat
> cat(addr[1])
#John Smith
#111 Main St.
#Portland, OR 97212
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该功能cat
只是打印到屏幕上.
另一个标准字符\t
用于制表符空间.
您需要将其与换行符 ( \n
) 分隔符粘贴在一起。从组装它df
,
addresses <- apply(df, 1, paste, collapse = '\n')
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如果你正常打印,它会显示\n
字符:
addresses
## [1] "John Smith\n111 Main St.\nPortland, OR 97212"
## [2] "Patty Smith\n222 Main St.\nPortland, OR 95212"
## [3] "Sam Smith\n555 C Street\nPortland, OR 99212"
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要使用评估的换行符打印cat
,还sep = '\n'
可以在项目之间插入换行符:
cat(addresses, sep = '\n')
## John Smith
## 111 Main St.
## Portland, OR 97212
## Patty Smith
## 222 Main St.
## Portland, OR 95212
## Sam Smith
## 555 C Street
## Portland, OR 99212
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