将容器组件嵌套在表示组件中

M M*_*ler 23 reactjs redux react-redux

我正在尝试重构我的应用程序以分离表示和容器组件.我的容器组件只是在connect()react-redux调用中包含的表示组件,它将状态和动作创建器映射到表示组件的道具.

待办事项,list.container.js

import React, {Component} from 'react';
import {connect} from 'react-redux';

import {fetchTodos} from '../actions/todo.actions';
import TodoList from '../components/todo-list.component';

export default connect(({todo}) => ({state: {todo}}), {fetchTodos})(TodoList);
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待办事项,list.component.jsx

import React, {Component} from 'react';

import TodoContainer from '../containers/todo.container';

export default class TodoList extends Component {
    componentDidMount () {
        this.props.fetchTodos();
    }

    render () {
        const todoState = this.props.state.todo;

        return (
            <ul className="list-unstyled todo-list">
                {todoState.order.map(id => {
                    const todo = todoState.todos[id];
                    return <li key={todo.id}><TodoContainer todo={todo} /></li>;
                })}
            </ul>
        );
    }
};
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todo.container.js

import React, {Component} from 'react';
import {connect} from 'react-redux';

import {createTodo, updateTodo, deleteTodo} from '../actions/todo.actions';
import Todo from '../components/todo.component';

export default connect(null, {createTodo, updateTodo, deleteTodo})(Todo);
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todo.component.jsx

import React, {Component} from 'react';

import '../styles/todo.component.css';

export default class Todo extends Component {
    render () {
        return (
            <div className="todo">
                {todo.description}
            </div>
        );
    }
};
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我想弄清楚的是:我知道我应该将<TodoContainer />元素嵌入其中,TodoList因为它TodoList是一个表示组件,它应该只嵌套其中的其他表示组件.但是如果我用一个<Todo />表示组件替换它,那么我必须映射每个状态prop和action creator prop,TodoListContainer因为Todo组件需要并将它们作为props手动传递到链中.这是我想要避免的事情,特别是如果我开始嵌套更多级别或开始依赖来自Redux的更多道具.

我接近这个吗?看起来我不应该试图将一个容器组件嵌入到一个表示组件中,因为如果我可以将表示组件与Redux分离,它们就会变得更加可重用.同时,我不知道如何嵌入需要访问具有标记的任何其他组件内的Redux状态/调度的组件.

Mar*_*cke 11

要专门回答你的问题:嵌套表示和容器组件是可以的.毕竟,它们都只是组件.然而,为了便于测试,我更喜欢将表示组件嵌套在容器组件上.这一切都归结为组件的清晰结构.我发现从单个文件开始然后慢慢组件化工作很好.

看一下嵌套孩子并利用this.props.children它们将子元素包装在一个表示元素中.

示例(为简洁起见,删除了一些代码)

清单(表示组件)

import React, { Component, PropTypes } from 'react';

export default class List extends Component {
  static propTypes = {
    children: PropTypes.node
  }

  render () {
    return (
      <div className="generic-list-markup">
        {this.props.children} <----- wrapping all children
      </div>
    );
  }
}
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Todo(演示组件)

import React, { Component, PropTypes } from 'react';

export default class Todo extends Component {
  static propTypes = {
    description: PropTypes.string.isRequired
  }

  render () {
    return (
      <div className="generic-list-markup">
        {this.props.description}
      </div>
    );
  }
}
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TodoList(容器组件)

import React, { Component, PropTypes } from 'react';
import { connect } from 'react-redux';
import { createTodo, updateTodo, deleteTodo } from 'actions';
import List from 'components/List';
import Todo from 'components/Todo';

export class TodoList extends Component {
  static propTypes = {
    todos: PropTypes.array.isRequired,
    create: PropTypes.func.isRequired
  }

  render () {
    return (
      <div>
        <List> <---------- using our presentational component
          {this.props.todos.map((todo, key) =>
            <Todo key={key} description={todo.description} />)}
        </List>
        <a href="#" onClick={this.props.create}>Add Todo</a>
      </div>
    );
  }
}

const stateToProps = state => ({
  todos: state.todos
});

const dispatchToProps = dispatch = ({
  create: () => dispatch(createTodo())
});

export default connect(stateToProps, dispatchToProps)(TodoList);
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DashboardView(表示组件)

import React, { Component } from 'react';
import TodoList from 'containers/TodoList';

export default class DashboardView extends Component {
  render () {
    return (
      <div>
        <TodoList />
      </div>
    );
  }
};
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