将.lua表转换为python字典

Question

我有这种输入：

    sometable = {
        ["a"] = {
            "a1",
        },
        ["b"] = {
            "b1",
            ["b2"] = true,
        },
        ["c"] = {
            "c1",
            ["c2"] = true,
        },
    },

并想将其转换为我可以在python中使用的字典-或基本上，我只需要能够以这种模式读取数据：

print sometable[b][b2]

最好的解决方案是什么？我试图做一堆替换并使用进行转换ast，即：

def make_dict(input): # just body, ie. without 'sometable'
    input = input.replace("=", ":")
    input = input.replace("[\"", "\"")
    input = input.replace("\"]", "\"")
    input = input.replace("\t", "")
    input = input.replace("\n", "")
    input = "{" + input + "}"
    return ast.literal_eval(input)

问题是输出是：

{
 "a" : 
  {"a1", },
 "b" : 
  {"b1", "b2" : true,},
 "c" : 
  {"c1", "c2" : 1,},
}

错误（invalid syntax）亮起{"b1", "b2" : true,},。有什么建议吗？

Answer 1

查看此包：https : //github.com/SirAnthony/slpp。

>>> from slpp import slpp as lua
>>> code = """{
    ["a"] = {
        "a1",
    },
    ["b"] = {
        "b1",
        ["b2"] = true,
    },
    ["c"] = {
        "c1",
        ["c2"] = true,
    },
}"""
>>> print(lua.decode(code))
{'a': ['a1'], 'c': {0: 'c1', 'c2': True}, 'b': {0: 'b1', 'b2': True}}