我有一个包含以下内容的文本文件:
"abc","def","ghi"
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以下工作正常读取文件内容:
int main()
{
char name[1024] = {0};
FILE *file = fopen("file.txt", "r");
while(1)
{
if (fscanf(file, " %[\",]s ", name) == EOF)
break;
if (fscanf(file, " %[a-zA-Z]s ", name) == EOF)
break;
printf("%s\n", name);
}
return 0;
}
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但是,以下失败:
int main()
{
char name[1024] = {0}, garbage[5];
FILE *file = fopen("file.txt", "r");
while(1)
{
if (fscanf(file, " %[\",]s%[a-zA-Z]s ", garbage, name) == EOF)
break;
printf("%s\n", name);
}
return 0;
}
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我正在使用MSVC++ 08.我错过了什么?我在寻找与单一的解决方案fscanf()中的while循环.
有用???纯粹运气不好:-)
您的转换规格意味着
" %[\",]s "
^= optionally skip whitespace
^== read a literal 's'
^^^^^^=== read an unlimited string of quotes and commas
^========= optionally skip whitespace
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和
" %[a-zA-Z]s "
^= optionally skip whitespace
^== read a literal 's'
^^^^^^^^^=== read an unlimited string of letters
^============ optionally skip whitespace
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和
" %[\",]s%[a-zA-Z]s "
^= optionally skip whitespace
^== read a literal 's'
^^^^^^^^^=== read an unlimited string of letters
^============ read a literal 's'
^^^^^^============= read an unlimited string of quotes and commas
^=================== optionally skip whitespace
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我想你想要的
" %4[\",]%1023[a-zA-Z] "
^= optionally skip whitespace
^^^^^^^^^^^^^== read a string of at most 1023 letters
^^^^^^^=============== read a string of at most 4 quotes and commas
^====================== optionally skip whitespace
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除此之外,scanf返回成功转换的次数或出错时的EOF.当您应该与1(或2或其他)进行比较时,您将结果值与EOF进行比较:与您期望的转化次数进行比较.
if (scanf() == 3) /* expected 3 conversions */
{ /* ok */ }
else { /* oops, something went wrong */ }
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