GraphQL将args传递给sub解析

Question

我和User之间有关系.这是我查询用户帖子的方式.

const UserType = new GraphQLObjectType({
  name: 'User'
  fields: () => ({
    name: {
      type: GraphQLString
    },
    posts: {
      type: new GraphQLList(PostType),
      resolve(parent, args , { db }) {
        // I want to get here the args.someBooleanArg
        return someLogicToGetUserPosts();
      }
    }
  })
});

主要查询是:

const queryType = new GraphQLObjectType({
  name: 'RootQuery',
  fields: {
    users: {
      type: new GraphQLList(UserType),
      args: {
        id: {
          type: GraphQLInt
        },
        someBooleanArg: {
          type: GraphQLInt
        }
      },
      resolve: (root, { id, someBooleanArg }, { db }) => {
        return someLogicToGetUsers();
      }
    }
  }
});

问题是UserType帖子的resolve函数中的args是空对象,我如何将args从主查询传递给子解析函数？

Answer 1

解析根查询时,可以使用对象分配将参数附加到返回的用户对象.然后,在用户类型上,从根值(解析函数的第一个参数)解析参数.

例:

const queryType = new GraphQLObjectType({
  name: 'RootQuery',
  fields: {
    users: {
      type: new GraphQLList(UserType),
      args: {
        id: {
          type: GraphQLInt
        },
        someBooleanArg: {
          type: GraphQLInt
        }
      },
      resolve: (root, { id, someBooleanArg }, { db }) => {
        return Promise.resolve(someLogicToGetUsers()).then(v => {
            return Object.assign({}, v, {
                someBooleanArg
            });
        });
      }
    }
  }
});

const UserType = new GraphQLObjectType({
  name: 'User'
  fields: () => ({
    name: {
      type: GraphQLString
    },
    posts: {
      type: new GraphQLList(PostType),
      resolve(parent, args , { db }) {
        console.log(parent.someBooleanArg);
        return someLogicToGetUserPosts();
      }
    }
  })
});