Spring:使用循环发送多条消息

Col*_*b1a 1 java spring spring-integration spring-xd spring-messaging

假设我在 Spring XD 中有一个自定义模块(我使用 Spring XD + Spring Integration + hibernate)。该模块基本上从数据库获取一些东西(假设我使用休眠实体存储它,所以我使用一个名为“DataFromDB”的对象)。DataFromDB 是一个列表,然后我从列表中获取每个元素,然后我想使用如下方式发送它:

String payload = convertDataFromDBToJson(record);
return MessageBuilder.createMessage(payload, message.getHeaders());
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  • 问题是每次我必须发送消息时我都必须返回消息。
  • 所以我想循环 DataFromDB 列表并将每个元素作为消息发送。

有没有办法发送多条消息?

编辑:

我只是根据尝试复制该场景的评论创建了一个小示例。这就是我所拥有的:

我的变压器类:

public class TransformerClass {
public Collection<Message<?>> transformerMethod(Message<?> message) {
    List<Message<?>> messages = new ArrayList<Message<?>>();
    messages.add(new GenericMessage<>("foo"));
    messages.add(new GenericMessage<>("bar"));
    return messages;
}
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我的xml配置:

    <?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:int="http://www.springframework.org/schema/integration"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/integration http://www.springframework.org/schema/integration/spring-integration.xsd
        http://www.springframework.org/schema/tx  http://www.springframework.org/schema/tx/spring-tx.xsd">

    <tx:annotation-driven />
    <int:channel id="input" />

    <bean id="transFormerClass" class="myModule.TransformerClass">
    </bean>

    <int:transformer input-channel="input" output-channel="output" ref="transFormerClass" method="transformerMethod"/>

    <int:channel id="output"/>

</beans>
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我的测试课:

    @ModuleName(value = "someModule", type = ModuleType.processor)
public class TransformerClassTest extends xDTest {
    private String streamName = "myStream";
    private String chainTest = "someModule";

    @SuppressWarnings("unchecked")
    @Test
    public void testPartnerNotification() throws IOException {

        this.chain = SingleNodeProcessingChainSupport.chain(application, streamName, chainTest);
        //Just to send something to the module as a input.
        Message<String> input = MessageBuilder.createMessage("hello world", buildHeaders());
        this.chain.send(input);
        //Receiving a Single message
        Message<String> result = (Message<String>) chain.receive(5000);
        System.out.println("Result: " + result);
    }

    private MessageHeaders buildHeaders() {
        Map<String, Object> hashMap = new HashMap<String,Object>();
        hashMap.put("test", "testing");
        MessageHeaders headers = new MessageHeaders(hashMap);
        return headers;
    }    
}
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输出是:

结果:genericMessage [有效载荷= [genericMessage [有效载荷= foo,headers = {timestamp = 1475072951345,id = 7b6c79a2-db85-563e-c238-c238-262a38-262a38-262a31141456}] -3513-b95e-3a25-4fd3550f2fea}]],标头={时间戳=1475072951347,id=f90d94c4-e323-70ed-62ee-4b8bce64814d,测试=测试}]

我正在使用 Spring Integration 4.2.2.RELEASE。

Gar*_*ell 5

如果您返回Collection<Message<?>>,它们将作为单独的消息发送。

编辑

@EnableIntegration
@Configuration
public class So39708474Application {

    @Bean
    public DirectChannel input() {
        return new DirectChannel();
    }

    @Bean
    public DirectChannel output() {
        return new DirectChannel();
    }

    @Bean
    public Foo foo() {
        return new Foo();
    }

    public static class Foo {

        @ServiceActivator(inputChannel = "input", outputChannel = "output")
        public Collection<Message<?>> handle(Message<?> in) {
            List<Message<?>> messages = new ArrayList<Message<?>>();
            messages.add(new GenericMessage<>("foo"));
            messages.add(new GenericMessage<>("bar"));
            return messages;
        }

    }

}
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@RunWith(SpringRunner.class)
@ContextConfiguration(classes = So39708474Application.class)
public class So39708474ApplicationTests {

    @Autowired
    private MessageChannel input;

    @Autowired
    private SubscribableChannel output;

    @Test
    public void contextLoads() {
        AtomicInteger count = new AtomicInteger();
        this.output.subscribe(m -> {
            count.incrementAndGet();
            System.out.println(m);
        });
        this.input.send(new GenericMessage<>("test"));
        assertEquals(2, count.get());
    }

}
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  • 我很困惑 - 你说你已经有一个自定义模块并且想要为一个输入消息创建多个输出消息。这正是将会发生的事情;你不需要分离器。如果你返回 `Collection&lt;Payload&gt;` 你会的,但是 `Collection&lt;Message&lt;?&gt;&gt;` 告诉框架你想要发送多个输出。 (2认同)