如何使用SQL Server 2008将行复制到同一个表中

Question

A)到目前为止我的方式:

sqlCommand.CommandText =
"INSERT Table1 ([column1],[column2],[column3])" +
            " SELECT [column1],[column2],[column3]" +
            " FROM Table1 WHERE Id =" + param +
            ";select scope_identity() as id";

B)我希望做这样的事情:

INSERT INTO "table1" (* (without the ID-column))
SELECT (* (without the ID-column))
FROM "table1"

注意:我正在复制到同一个表.我只是想轻松地将它全部复制到另一行,而当然给新行一个新的ID.

这是好的做法,可能与否？

Answer 1

执行此操作的唯一方法是列出第一个示例中的所有列.没有类似的语法SELECT *, -Id

您应该使用参数化SQL来进行SQL注入和计划缓存.

Answer 2

我自己也有同样的问题,想要一个简单明了的方法.

我在这里找到了一个解决方案.我稍微修改了它以删除输出ID,并使IdColumnName的默认值为'Id'.

IF OBJECT_ID('TableRowCopy') IS NOT NULL DROP PROCEDURE TableRowCopy
GO
SET ANSI_NULLS ON
SET QUOTED_IDENTIFIER ON
GO
CREATE PROCEDURE [dbo].[TableRowCopy](
    @TableName VARCHAR(50),
    @WhereIdValue INT,
    @IdColumnName VARCHAR(50) = 'Id'
)
AS
BEGIN
    DECLARE @columns VARCHAR(5000), @query VARCHAR(8000);
    SET @query = '' ;

    SELECT @columns =
        CASE
            WHEN @columns IS NULL THEN column_name
            ELSE @columns + ',' + column_name
        END
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE (
        TABLE_NAME = LTRIM(RTRIM(@TableName))
        AND
        column_name != LTRIM(RTRIM(@IdColumnName))
    );

    SET @query = 'INSERT INTO ' + @TableName + ' (' + @columns + ') SELECT ' + @columns + ' FROM ' + @TableName + ' WHERE ' + @IdColumnName + ' = ' + CAST(@WhereIdValue AS VARCHAR);
    EXEC (@query);
    SELECT SCOPE_IDENTITY();
END

用法示例:

EXEC TableRowCopy 'MyTable', 3