如何在django rest框架中上传多个文件

Question

在django rest框架中,我可以使用danialfarid/ng-file-upload上传单个文件

views.py:

class PhotoViewSet(viewsets.ModelViewSet):
    serializer_class = PhotoSerializer
    parser_classes = (MultiPartParser, FormParser,)
    queryset=Photo.objects.all()

    def perform_create(self, serializer):
        serializer.save(blogs=Blogs.objects.latest('created_at'),
                   image=self.request.data.get('image'))

serializers.py:

class PhotoSerializer(serializers.ModelSerializer):
    class Meta:
        model = Photo

models.py:

class Photo(models.Model):
    blogs = models.ForeignKey(Blogs, related_name='blogs_img')
    image = models.ImageField(upload_to=content_file_name)

当我尝试上传多个文件时.我进去了

chrome开发人员工具:请求有效负载

------WebKitFormBoundaryjOsYUxPLKB1N69Zn
Content-Disposition: form-data; name="image[0]"; filename="datacable.jpg"
Content-Type: image/jpeg


------WebKitFormBoundaryjOsYUxPLKB1N69Zn
Content-Disposition: form-data; name="image[1]"; filename="datacable2.jpg"
Content-Type: image/jpeg

响应:

{"image":["No file was submitted."]}

我不知道如何编写用于上传多个文件的序列化程序.任何身体请帮助.

提前致谢

Answer 1

我设法解决这个问题,我希望它能帮助社区

serializers.py:

class FileListSerializer ( serializers.Serializer ) :
    image = serializers.ListField(
                       child=serializers.FileField( max_length=100000,
                                         allow_empty_file=False,
                                         use_url=False )
                                )
    def create(self, validated_data):
        blogs=Blogs.objects.latest('created_at')
        image=validated_data.pop('image')
        for img in image:
            photo=Photo.objects.create(image=img,blogs=blogs,**validated_data)
        return photo

class PhotoSerializer(serializers.ModelSerializer):

    class Meta:
        model = Photo
        read_only_fields = ("blogs",)

views.py:

class PhotoViewSet(viewsets.ModelViewSet):
    serializer_class = FileListSerializer
    parser_classes = (MultiPartParser, FormParser,)
    queryset=Photo.objects.all()

Answer 2

我不太清楚，但这是有效的......这是我的视图集。

def perform_create(self, serializer):
    obj = serializer.save()
    for f in self.request.data.getlist('files'):
        mf = MyFile.objects.create(file=f)
        obj.files.add(mf)