在Python中,我如何切割列表列表并获得列表的子列表而不是numpy?
例如,从A [1] [1]到A [2] [2]获取列表并将其存储在B中:
A = [[1, 2, 3, 4 ],
[11, 12, 13, 14],
[21, 22, 23, 24],
[31, 32, 33, 34]]
B = [[12, 13],
[22, 23]]
Run Code Online (Sandbox Code Playgroud)
您可以切片 A及其子列表:
In [1]: A = [[1, 2, 3, 4 ],
...: [11, 12, 13, 14],
...: [21, 22, 23, 24],
...: [31, 32, 33, 34]]
In [2]: B = [l[1:3] for l in A[1:3]]
In [3]: B
Out[3]: [[12, 13], [22, 23]]
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
502 次 |
| 最近记录: |