Wpf Popup放置

Question

我有没有机会在ListBox的项目旁边放置弹出窗口？我使用MVVM,list绑定到元素,对于一些选择的元素,我想在项目旁边显示弹出窗口.

我有元素列表,我想在单击指定的列表元素时显示弹出窗口,但弹出窗口应显示在所选列表项旁边.

我试过这样的事情(它不起作用):

    <Popup  IsOpen="{Binding Path=ShowPopup}" PlacementTarget="{Binding ElementName=List1, Path=SelectedItem}" Placement="Center">
        <TextBox Background="Red" Height="120" Text="Aaaaaa FUUUUUUUUUUUUU....."></TextBox>
    </Popup>

我不想使用后面的代码,只有xaml

Answer 1

这会将弹出窗口放在所选ListBoxItem的右侧

例

<Window.Resources>
    <SolidColorBrush x:Key="SelectedBackgroundBrush" Color="#DDD" />
    <SolidColorBrush x:Key="DisabledForegroundBrush" Color="#888" />

    <ControlTemplate x:Key="PopupListBoxItemTemplate" TargetType="ListBoxItem">
        <Border Name="Border" Padding="2" SnapsToDevicePixels="true">
            <Grid>
                <Popup Name="c_popup" PlacementTarget="{Binding RelativeSource={RelativeSource TemplatedParent}}" Placement="Right" >
                    <Border BorderBrush="Black" BorderThickness="1" CornerRadius="2.5">
                        <TextBlock Background="Wheat" Foreground="Black" Text="Aaaaaa FUUUUUUUUUUUUU....."/>
                    </Border>
                </Popup>
                <ContentPresenter />
            </Grid>
        </Border>
        <ControlTemplate.Triggers>
            <Trigger Property="IsSelected" Value="true">
                <Setter TargetName="Border" Property="Background" Value="{StaticResource SelectedBackgroundBrush}"/>
                <Setter TargetName="c_popup" Property="IsOpen" Value="True"/>
            </Trigger>
            <Trigger Property="IsEnabled" Value="false">
                <Setter Property="Foreground" Value="{StaticResource DisabledForegroundBrush}"/>
            </Trigger>
        </ControlTemplate.Triggers>
    </ControlTemplate>
</Window.Resources>
<Grid>
    <ListBox Name="listBox"
             ItemsSource="{Binding Source={x:Static Fonts.SystemFontFamilies}}">
        <ListBox.ItemContainerStyle>
            <Style TargetType="{x:Type ListBoxItem}">
                <Setter Property="Template" Value="{StaticResource PopupListBoxItemTemplate}" />
            </Style>
        </ListBox.ItemContainerStyle>
    </ListBox>
</Grid>

Answer 2

由于您想在单击该项目时显示弹出窗口，因此这对您有用：

<Popup  IsOpen="{Binding Path=ShowPopup}" Placement="Mouse">
     <TextBox Background="Red" Height="120" Text="Aaaaaa FUUUUUUUUUUUUU....."></TextBox>
 </Popup>