Django Restul返回绝对URL

Question

所以我有一个相当直接的序列化器 serializers.py

class ScheduleSerializer(serializers.ModelSerializer):

    class Meta:
        model = FrozenSchedule
        fields = ['startDate', 'endDate', 'client', 'url']

    startDate = serializers.DateField(source='start_date')
    endDate = serializers.DateField(source='end_date')
    client = serializers.StringRelatedField(many=False)
    url = serializers.URLField(source='get_absolute_url')

get_absolute_url 在我的 models.py

def get_absolute_url(self):
    return reverse('reports:frozenschedule-detail', kwargs={
        'slug': self.client.slug, 'pk': self.id
    })

它与ViewSet相关 viewsets.py

class ScheduleViewSet(viewsets.ReadOnlyModelViewSet):
    queryset = FrozenSchedule.objects.not_abandoned().future()\
        .filter(signed=False).order_by('start_date')
    serializer_class = serializers.ScheduleSerializer

它返回JSON,如下所示:

 [
    {
        "startDate": "2016-10-01",
        "endDate": null,
        "client": "Abscissa.Com Limited",
        "url": "/clients/abscissac/frozenschedule/1",
    }
]

但我希望它返回完整的URL,而不仅仅是相对路径

[
    {
        "startDate": "2016-10-01",
        "endDate": null,
        "client": "Abscissa.Com Limited",
        "url": "http://localhost:8000/clients/abscissac/frozenschedule/1",
    }
]

我可以在我的Serializer中以这种方式序列化URL吗？

Restful文档说明rest_framework reverse函数完全符合我的需要.但它需要请求对象来构建UR http://www.django-rest-framework.org/api-guide/reverse/

Answer 1

覆盖HyperlinkedIdentityField.

class UrlHyperlinkedIdentityField(HyperlinkedIdentityField):
   def get_url(self, obj, view_name, request, format):
     if obj.pk is None:
       return None

    return self.reverse(view_name,
        kwargs={
            'slug': obj.client.slug,
            'pk': obj.id,
        },
        request=request,
        format=format,
    )

然后在 serializers.py:

url = UrlHyperlinkedIdentityField(view_name='reports:frozenschedule-detail')