如何删除Ruby中字符串中的最后一个元音？

Question

如何在字符串中定义-last元音？

例如,我有一个单词"经典"

我想找到"classs i c" 这个词的最后一个元音是字母" i ",并删除最后一个元音.

我在想 :

def vowel(str)
  result = ""
  new = str.split(" ")
  i = new.length - 1
  while i < new.length
    if new[i] == "aeiou"
      new[i].gsub(/aeiou/," ")
    elsif new[i] != "aeiou"
      i = -= 1
    end
  end
  return result
end

Answer 1

r = /
    .*      # match zero or more of any character, greedily
    \K      # discard everything matched so far
    [aeiou] # match a vowel
    /x      # free-spacing regex definition mode

"wheelie".sub(r,'') #=> "wheeli"
"though".sub(r,'')  #=> "thogh"
"why".sub(r,'')     #=> "why"