使用angular-cli webpack创建多个包

Question

当我使用angular-cli构建项目时,它将所有项目文件捆绑到一个大的主要包中.

我在应用程序中使用了延迟路由,一旦应用程序加载,我就可以正常导航.

有没有一种方法可以根据延迟加载的路由模块将主包分成多个文件？

以下是配置 angular-cli.json

    {
  "project": {
    "version": "1.0.0-beta.15",
    "name": "maddy-test-project"
  },
  "apps": [
    {
      "root": "src",
      "outDir": "dist",
      "assets": "styles/content",
      "index": "default.htm",
      "main": "main.ts",
      "test": "test.ts",
      "tsconfig": "tsconfig.json",
      "prefix": "",
      "mobile": false,
      "styles": [
        "styles.less"
      ],
      "scripts": [
        "styles/wfa-myriad-pro-typekit.js"
      ],
      "environments": {
        "source": "environments/environment.ts",
        "dev": "environments/environment.ts",
        "prod": "environments/environment.prod.ts"
      }
    }
  ],
  "addons": [],
  "packages": [],
  "e2e": {
    "protractor": {
      "config": "./protractor.conf.js"
    }
  },
  "test": {
    "karma": {
      "config": "./karma.conf.js"
    }
  },
  "defaults": {
    "styleExt": "less",
    "prefixInterfaces": false
  }
}

下面是package.json

{
  "name": "maddy-test-project",
  "version": "0.0.1",
  "license": "MIT",
  "angular-cli": {},
  "scripts": {
    "start": "ng serve",
    "lint": "tslint \"src/**/*.ts\"",
    "test": "ng test",
    "pree2e": "webdriver-manager update",
    "e2e": "protractor"
  },
  "private": true,
  "dependencies": {
    "@angular/common": "2.0.0",
    "@angular/compiler": "2.0.0",
    "@angular/core": "2.0.0",
    "@angular/forms": "2.0.0",
    "@angular/http": "2.0.0",
    "@angular/platform-browser": "2.0.0",
    "@angular/platform-browser-dynamic": "2.0.0",
    "@angular/router": "3.0.0",
    "d3": "^4.2.3",
    "jquery": "^3.1.0",
    "lodash": "^4.15.0",
    "moment": "^2.15.0",
    "core-js": "^2.4.1",
    "rxjs": "5.0.0-beta.12",
    "toastr": "^2.1.2",
    "ts-helpers": "^1.1.1",
    "zone.js": "^0.6.23",  
    "bootstrap-daterangepicker": "^2.1.24"
  },
  "devDependencies": {
    "@types/d3": "^3.5.35",
    "@types/google-maps": "^3.1.27",
    "@types/jasmine": "^2.2.30",
    "@types/jquery": "^1.10.31",
    "@types/lodash": "^4.14.34",
    "@types/toastr": "^2.1.29",
    "angular-cli": "1.0.0-beta.15",
    "codelyzer": "~0.0.26",
    "jasmine-core": "2.4.1",
    "jasmine-spec-reporter": "2.5.0",
    "karma": "1.2.0",
    "karma-chrome-launcher": "^2.0.0",
    "karma-cli": "^1.0.1",
    "karma-jasmine": "^1.0.2",
    "karma-remap-istanbul": "^0.2.1",
    "protractor": "4.0.5",
    "ts-node": "1.2.1",
    "tslint": "3.13.0",
    "typescript": "2.0.2"
  }
}

提前致谢!!

Answer 1

它是NgModule和RouterModule.forChild()的角色.这是一篇非常好的文章,用于启动大型Angular 2模块化应用程序开发:http://blog.angular-university.io/angular2-ngmodule/

我们需要做的第一件事是从App组件和主路由配置中删除每个提到的Home组件或HomeModule:

我们在这里可以看到App组件不再导入HomeModule,而是路由配置使用loadChildren来表示如果/ home或任何其他以它开头的url被命中,那么应该通过Ajax调用加载文件home.module.

不久,要在惰性模块中移动一些逻辑和组件,您可以运行以下命令:

ng g module child --routing

然后angular-cli将生成NgModule(app/child/child.module.ts)和子路由器配置(app/child/child-routing.module.ts).

延迟加载此子路由器的路由将是:

 { path: 'child', loadChildren: 'app/child/child.module#ChildModule' }

最后用一个约束在ChildModule中移动你想要的东西:其他模块(如AppModule)将无法使用任何ChildModule依赖(例如服务).如果您需要它,一个好的做法是创建一个共享模块.