mic*_*ahr 9 java hibernate jpa hibernate-mapping
我们的问题是,由于源自Hibernate ,我们无法从遗留数据库中获取数据(包括长度为0的空字符串).我们想改变Hibernate的行为以正确解析空字符串.StringIndexOutOfBoundsExceptiionCharacterTypeDescriptor
示例数据:
1, 'Berlin', 17277, '', 'aUser'
2, 'London', 17277, '', 'anotherUser'
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我们使用hibernate javax.persistence.Query.
String sql = "SELECT * FROM table";
Query query = entityManager.createNativeQuery(sql);
List resultList = query.getResultList();
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这导致StringIndexOutOfBoundsException它的根是来自Hibernate的以下代码:
if ( String.class.isInstance( value ) ) {
final String str = (String) value;
return Character.valueOf( str.charAt(0) ); // this fails, as there is no char at position 0
}
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hibernate论坛上的帖子证实了这一点.
我们没有选择从这个错误的版本升级hibernate,并寻找一种方法来改变Hibernate的映射.
我们不能使用PreparedStatements或普通的JDBC-Connections,也不能使用JPA-Entities.
也不可能改变遗留数据库.SQL语句使用DBVisualizer完美运行.
有没有改变Hibernate映射字符串的方式?
东pe !!
事实上,因为这是一个非常好的问题,我决定写一篇文章来演示如何使用自定义Hibernate Type轻松实现这一目标.
首先,您需要定义CharacterType:
public abstract class ImmutableType<T> implements UserType {
private final Class<T> clazz;
protected ImmutableType(Class<T> clazz) {
this.clazz = clazz;
}
@Override
public Object nullSafeGet(
ResultSet rs,
String[] names,
SharedSessionContractImplementor session,
Object owner)
throws SQLException {
return get(rs, names, session, owner);
}
@Override
public void nullSafeSet(
PreparedStatement st,
Object value,
int index,
SharedSessionContractImplementor session)
throws SQLException {
set(st, clazz.cast(value), index, session);
}
protected abstract T get(
ResultSet rs,
String[] names,
SharedSessionContractImplementor session,
Object owner) throws SQLException;
protected abstract void set(
PreparedStatement st,
T value,
int index,
SharedSessionContractImplementor session)
throws SQLException;
@Override
public Class<T> returnedClass() {
return clazz;
}
@Override
public boolean equals(Object x, Object y) {
return Objects.equals(x, y);
}
@Override
public int hashCode(Object x) {
return x.hashCode();
}
@Override
public Object deepCopy(Object value) {
return value;
}
@Override
public boolean isMutable() {
return false;
}
@Override
public Serializable disassemble(Object o) {
return (Serializable) o;
}
@Override
public Object assemble(
Serializable cached,
Object owner) {
return cached;
}
@Override
public Object replace(
Object o,
Object target,
Object owner) {
return o;
}
}
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现在,我们可以转向定义实际CharacterType:
public class CharacterType
extends ImmutableType<Character> {
public CharacterType() {
super(Character.class);
}
@Override
public int[] sqlTypes() {
return new int[]{Types.CHAR};
}
@Override
public Character get(
ResultSet rs,
String[] names,
SharedSessionContractImplementor session,
Object owner)
throws SQLException {
String value = rs.getString(names[0]);
return (value != null && value.length() > 0) ?
value.charAt(0) : null;
}
@Override
public void set(
PreparedStatement st,
Character value,
int index,
SharedSessionContractImplementor session)
throws SQLException {
if (value == null) {
st.setNull(index, Types.CHAR);
} else {
st.setString(index, String.valueOf(value));
}
}
}
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实体映射如下所示:
@Entity(name = "Event")
@Table(name = "event")
public class Event {
@Id
@GeneratedValue
private Long id;
@Type(type = "com.vladmihalcea.book.hpjp.hibernate.type.CharacterType")
@Column(name = "event_type")
private Character type;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public Character getType() {
return type;
}
public void setType(Character type) {
this.type = type;
}
}
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我们假设我们有这些表行:
INSERT INTO event (id, event_type) VALUES (1, 'abc');
INSERT INTO event (id, event_type) VALUES (2, '');
INSERT INTO event (id, event_type) VALUES (3, 'b');
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阅读所有实体时:
doInJPA(entityManager -> {
List<Event> events = entityManager.createQuery(
"select e from Event e", Event.class)
.getResultList();
for(Event event : events) {
LOGGER.info("Event type: {}", event.getType());
}
});
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你会得到预期的输出:
Event type: a
Event type:
Event type: b
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查看GitHub上的源代码.