熊猫:连接数据帧

Question

我有2个数据帧

category    count_sec_target
 3D-??????  0.09375
 C??????    201.90625
 GPS ? ???????  0.015625
 Hi-Tech    187.1484375
 ????????????   0.8125
 ????????????   8.40625

和

category    count_sec_random
 3D-??????  0.369565217
 Hi-Tech    70.42391304
 ??? ??,  ???????????????   0.934782609
 ????????????   1.413043478
 ????????????   14.93478261
 ????   480.3369565

我需要连接并得到

category    count_sec_target    count_sec_random
 3D-??????  0.09375    0.369565217
 C??????    201.90625   0
 GPS ? ???????  0.015625   0
 Hi-Tech    187.1484375   70.42391304
 ????????????   0.8125   1.413043478
 ????????????   8.40625   14.93478261
 ??? ??,  ???????????????   0    0.934782609
 ????   0     480.3369565

接下来我想在col中划分值(count_sec_target / count_sec_random) * 100% 但是当我尝试连接df时

frames = [df1, df1]
df = pd.concat(frames)
I get 
category  count_sec_random  count_sec_target
 0                        3D-??????          0.369565               NaN
 1                          Hi-Tech         70.423913               NaN
 2         ??? ??,  ???????????????          0.934783               NaN
 3                     ????????????          1.413043               NaN
 4                     ????????????         14.934783               NaN

另外我试试df = df1.append(df2) BUt我得错了结果.我该如何解决这个问题？

Answer 1

df3 = pd.concat([d.set_index('category') for d in frames], axis=1).fillna(0)
df3['ratio'] = df3.count_sec_random / df3.count_sec_target
df3

设置参考

import pandas as pd
from StringIO import StringIO

t1 = """category;count_sec_target
3D-??????;0.09375
C??????;201.90625
GPS ? ???????;0.015625
Hi-Tech;187.1484375
????????????;0.8125
????????????;8.40625"""

t2 = """category;count_sec_random
3D-??????;0.369565217
Hi-Tech;70.42391304
??? ??,  ???????????????;0.934782609
????????????;1.413043478
????????????;14.93478261
????;480.3369565"""

df1 = pd.read_csv(StringIO(t1), sep=';')
df2 = pd.read_csv(StringIO(t2), sep=';')

frames = [df1, df2]