Codeigniter:加入不使用相同名称和ID的列

Question

我希望能够加入两张桌子togeather.

如何过,因为我我的论坛表有column "name"和我forum_categories column "name"

我无法显示这两个名字.

在我的select()上如果我使用$this->db->select('f.name, fc.name', false);它只显示来自forum_categories的名称

array(1) { [0]=> array(1) { ["name"]=> string(17) "News & Discussion" } }

问我如何从列和表中显示两个名称.

注意:我只希望能够$result['name']在我的foreach循环中使用.

所以我希望它能成为现实

General

News & Discussion

Lounge

我看过了

JOIN语句中的CodeIgniter ActiveRecord字段名称

codeigniter - 从具有相同列名的2个表中选择

模型

public function get_forums() {
    $this->db->select('f.name, fc.name', false);
    $this->db->from('forum as f');

    // tried $this->db->join('forum_categories as fc', 'fc.forum_id = f.forum_id');

    $this->db->join('forum_categories as fc', 'fc.forum_categories_id = f.forum_id');
    $query = $this->db->get();

    if ($query->num_rows() > 0) {
        return $query->result_array();
    } else {
        return false;
    }
}

调节器

<?php

class Forums extends MY_Controller {

    public function __construct() {
        parent::__construct();
    }

    public function index() {

        $data['label'] = '';

        $data['forums'] = array();

        $results = $this->get_forums();

        var_dump($results);

        if (isset($results)) {
            foreach ($results as $result) {

                $data['forums'][] = array(

                    'name' => $result['name'], // Only want to use single variable.

                );
            }
        }

        $data['header'] = Modules::run('admin/common/header/index');
        $data['footer'] = Modules::run('admin/common/footer/index');

        $this->load->view('template/forum/list_forum_view', $data);
    }

    public function get_forums() {
        $this->db->select('f.name, fc.name', false);
        $this->db->from('forum as f');
        $this->db->join('forum_categories as fc', 'fc.forum_categories_id = f.forum_id');
        $query = $this->db->get();

        if ($query->num_rows() > 0) {
            return $query->result_array();
        } else {
            return false;
        }
    }
}

更新

使用下面的代码工作正常,但宁愿只使用一个join()

public function get_forums() {
    $this->db->select("*");
    $this->db->from('forum');
    $query = $this->db->get();

    foreach ($query->result_array() as $f) {
        $data[] = array(
            'name' => $f['name']
        );

        $this->db->select("*");
        $this->db->from('forum_categories');
        $query = $this->db->get();

        foreach ($query->result_array() as $fc) {
            $data[] = array(
                'name' => $fc['name']
            );
        }

    }

    return $data;
}

Answer 1

试试看，它会起作用。

    public function get_forums() {
    $this->db->select('f.name as forum_name, fc.name as forum_categories_name', false);
    $this->db->from('forum f');

    // tried $this->db->join('forum_categories fc', 'fc.forum_id = f.forum_id');

    $this->db->join('forum_categories fc', 'fc.forum_categories_id = f.forum_id');
    $query = $this->db->get();

    if ($query->num_rows() > 0) {
        return $query->result_array();
    } else {
        return false;
    }
}

Answer 2

从我在你更新的问题中看到的。你需要的是UNION和不是JOIN。您可以使用get_compiled_select()在与 UNION 连接之前构建两个查询。

public function get_forums() {
    $forum = $this->db->select('name')->get_compiled_select('forum');
    $forum_categories = $this->db->select('name')->get_compiled_select('forum_categories');

    $query = $this->db->query($forum.' UNION '.$forum_categories);

    if ($query->num_rows() > 0) {
        return $query->result_array();
    } else {
        return false;
    }
}