kid*_*n01 1 api-design flask flask-sqlalchemy marshmallow
我目前正在使用 Flask、SQLAlchemy 和 Marshmallow 构建 API。我有一个相当简单的数据库模型,如下所示:
class Transaction(db.Model):
#Transaction Model
__tablename__ = 'transactions'
id = db.Column(db.Integer, primary_key = True)
created_at = db.Column(db.DateTime, default=datetime.datetime.now)
date = db.Column(db.DateTime)
description = db.Column(db.Text)
amount = db.Column(db.Float)
category_id = db.Column(db.Integer, db.ForeignKey('categories.id'))
category = db.relationship('Category', uselist=False, lazy='select')
sub_category_id = db.Column(db.Integer, db.ForeignKey('sub_categories.id'))
sub_category = db.relationship('SubCategory', uselist=False, lazy='select')
account = db.Column(db.Integer, db.ForeignKey('accounts.id'))
inner_transfer = db.Column(db.Boolean)
class Category(db.Model):
__tablename__ = 'categories'
id = db.Column(db.Integer, primary_key = True)
category = db.Column(db.String(64), unique = True)
transaction = db.relationship('Transaction')
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我的棉花糖架构如下所示:
class CategorySchema(ma.ModelSchema):
class Meta:
model = Category
category_schema = CategorySchema()
categories_schema = CategorySchema(many=True)
class TransactionSchema(ma.ModelSchema):
class Meta:
model = Transaction
include_fk = True
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还有一个非常简单的 API 端点:
@api.route('/transactions', methods=['GET'])
def transactions():
all_transactions = Transaction.query.all()
for transaction in all_transactions:
transaction.category = Category.query.filter_by(id=transaction.category_id).first()
print(transaction.category)
items, errors = transactions_schema.dump(all_transactions)
return jsonify(items)
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我现在的问题是:如何构建一个包含类别名称而不是主键的 JSON 响应?我尝试了“for transaction in all transactions”位,在打印语句中我得到了类别名称,但它没有显示在我的 JSON 响应中......
我不完全确定如何编写数据库模型。我特别坚持的是 db.relationship。在我的 Transaction 类中声明它似乎没有帮助,因为它也只显示了 Category 类的主键。我上下阅读了 Flask-SQLAlchemy 文档,但我一无所知。
非常感谢任何帮助和指示!
谢谢!
我创建了一个简单版本的模型来展示这一点,并用两条测试记录为 db 设置种子:
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_marshmallow import Marshmallow
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:////tmp/test.db'
db = SQLAlchemy(app)
ma = Marshmallow(app)
# DB Models
class Transaction(db.Model):
#Transaction Model
__tablename__ = 'transactions'
id = db.Column(db.Integer, primary_key = True)
category_id = db.Column(db.Integer, db.ForeignKey('categories.id'))
category = db.relationship('Category', uselist=False, lazy='select')
class Category(db.Model):
__tablename__ = 'categories'
id = db.Column(db.Integer, primary_key = True)
category = db.Column(db.String(64), unique = True)
transaction = db.relationship('Transaction')
# Schema
class TransactionSchema(ma.ModelSchema):
class Meta:
model = Transaction
include_fk = True
# Here is the function, you do not not need to define all fields you want to dump
category_name = ma.Function(lambda obj: obj.category.category)
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然后调用:
TransactionSchema(many=True).dump(Transaction.query.all()).data
产量:
[{u'category': 1, u'category_id': 1, u'category_name': u'Test1', u'id': 1},
{u'category': 2, u'category_id': 2, u'category_name': u'Test2', u'id': 2}]
也可以使用函数覆盖您的字段并使其仅转储:
class TransactionSchema(ma.ModelSchema):
class Meta:
model = Transaction
include_fk = True
category = ma.Function(lambda obj: obj.category.category, dump_only=True)
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产量:
[{u'category': u'Test1', u'category_id': 1, u'id': 1},
{u'category': u'Test2', u'category_id': 2, u'id': 2}]
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