如何在NGINX中获取URL的子域名

Str*_*ch0 5 nginx url-redirection devops

我想根据用户输入的子域进行重定向.

例如:

<subdomain>.example.com/admin -> <subdomain>.myurl.com

理想情况下,我想将<subdomain>参数作为参数传递给我的重定向网址.

我正在寻找与此类似的东西:

location ~ (sub).(somewhere).(com)/(some)(thing)/(something)(else) {
  set $var1 = $1; # = sub in above example
  set $var2 = $2; # = somewhere in above example
  set $var3 = $3; # = com in above example
  set $var4 = $4; # = some in above example
  set $var5 = $5; # = thing in above example
  set $var6 = $6; # = something in above example
  set $var7 = $7; # = else in above example
  rewrite ^ $1/$2 last; # would be sub/somewhere
}
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基于这篇文章在这里:操纵或拆分字符串(我认为变量集的语法在这个例子中是错误的,但你得到了要点).

Ric*_*ith 8

URL的域名部分未经location指令测试.您需要在server_name指令中使用命名捕获.请参阅此文档了解详细信息

例如:

server {
    server_name ~^(?<name>\w+)\.example\.com$;

    location /admin {
        return 301 $scheme://$name.myurl.com/;
    }
}
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  • 正则表达式与 URL 中带有“-”的 URL 不匹配。更好的方法是使用: `server_name ~^(?&lt;name&gt;[\w-]+)\.example\.com$;` (3认同)