Car*_*orc 5 python typing python-3.5
我有这个非常简单的代码:
from typing import List, Iterable
Position = (int, int)
IntegerMatrix = List[List[int]]
def locate_zeros(matrix: IntegerMatrix) -> Iterable[Position]:
"""Given an NxM matrix find the positions that contain a zero."""
for row_num, row in enumerate(matrix):
for col_num, element in enumerate(row):
if element == 0:
yield (col_num, row_num)
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这是错误:
Traceback (most recent call last):
File "type_m.py", line 6, in <module>
def locate_zeros(matrix: IntegerMatrix) -> Iterable[Position]:
File "/usr/lib/python3.5/typing.py", line 970, in __getitem__
(len(self.__parameters__), len(params)))
TypeError: Cannot change parameter count from 1 to 2
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为什么我不能将一对可迭代的Int对作为返回类型?
无论-> Position和Iterable[Any]工作,只是没有Iterable和Position在一起没有.
您应该使用typing.Tuple[int, int]声明元组类型Position,而不是(int, int).
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