如何在Javascript中过滤json对象？

Question

我有以下json字符串:

{
   "Alarm":{
      "Hello":48,
      "World":3,
      "Orange":1
   },
   "Rapid":{
      "Total":746084,
      "Fake":20970,
      "Cancel":9985,
      "Word": 2343
   },
   "Flow":{
      "Support":746084,
      "About":0,
      "Learn":0
   }
}

然后我加载上面的字符串并将其转换为json对象:

jsonStr = '{"Alarm":{"Hello":48,"World":3,"Orange":1},"Rapid":{"Total":746084,"Fake":20970,"Cancel":9985},"Flow":{"Support":746084,"About":0,"Learn":0}}';
var jsonObj = JSON.parse(jsonStr);

现在我如何json通过键名过滤此对象？例如,如果过滤器是"ange",则过滤的对象将是:

{
   "Alarm":{
      "Orange":1
   }
}

如果过滤器是"flo",则过滤后的对象将变为:

{
   "Flow":{
      "Support":746084,
      "About":0,
      "Learn":0
   }
}

如果过滤器是"wor",结果将是:

{
   "Alarm":{
      "World":3,
   },
   "Rapid":{
      "Word": 2343
   }
}

是否可以使用该filter方法实现此过滤？任何意见,将不胜感激.

Answer 1

除了给定的解决方案,您还可以使用递归样式来检查密钥.

此提议提供了在内部拥有更多嵌套对象并仅获取已过滤部分的机会.

function filterBy(val) {
    function iter(o, r) {
        return Object.keys(o).reduce(function (b, k) {
            var temp = {};
            if (k.toLowerCase().indexOf(val.toLowerCase()) !== -1) {
                r[k] = o[k];
                return true;
            }
            if (o[k] !== null && typeof o[k] === 'object' && iter(o[k], temp)) {
                r[k] = temp;
                return true;
            }
            return b;
        }, false);
    }

    var result = {};
    iter(obj, result);
    return result;
}

var obj = { Alarm: { Hello: 48, "World": 3, Orange: 1 }, Rapid: { Total: 746084, Fake: 20970, Cancel: 9985, Word: 2343 }, Flow: { Support: 746084, About: 0, Learn: 0 }, test: { test1: { test2: { world: 42 } } } };

console.log(filterBy('ange'));
console.log(filterBy('flo'));
console.log(filterBy('wor'));

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

您可以通过创建函数reduce()和Object.keys(),将检查与键名indexOf(),并返回所需的结果.

var obj = {
  "Alarm": {
    "Hello": 48,
    "World": 3,
    "Orange": 1
  },
  "Rapid": {
    "Total": 746084,
    "Fake": 20970,
    "Cancel": 9985,
    "Word": 2343
  },
  "Flow": {
    "Support": 746084,
    "About": 0,
    "Learn": 0
  }
}

function filterBy(val) {
  var result = Object.keys(obj).reduce(function(r, e) {
    if (e.toLowerCase().indexOf(val) != -1) {
      r[e] = obj[e];
    } else {
      Object.keys(obj[e]).forEach(function(k) {
        if (k.toLowerCase().indexOf(val) != -1) {
          var object = {}
          object[k] = obj[e][k];
          r[e] = object;
        }
      })
    }
    return r;
  }, {})
  return result;
}

console.log(filterBy('ange'))
console.log(filterBy('flo'))
console.log(filterBy('wor'))