说我有以下型号:
class Department(Base):
__tablename__ = 'departments'
id = Column(Integer, primary_key=True)
class Employee(Base):
__tablename__ = 'employees'
id = Column(Integer, primary_key=True)
department_id = Column(None, ForeignKey(Department.id), nullable=False)
department = relationship(Department, backref=backref('employees'))
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有时,当我查询部门时,我还想获取他们拥有的员工数量.我可以用a来实现这一点column_property,如下:
Department.employee_count = column_property(
select([func.count(Employee.id)])
.where(Employee.department_id == Department.id)
.correlate_except(Employee))
Department.query.get(1).employee_count # Works
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但是,即使我不需要,也总是通过子查询获取计数.显然我不能要求SQLAlchemy在查询时不加载它:
Department.query.options(noload(Department.employee_count)).all()
# Exception: can't locate strategy for <class 'sqlalchemy.orm.properties.ColumnProperty'> (('lazy', 'noload'),)
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我也尝试使用混合属性而不是列属性来实现它:
class Department(Base):
#...
@hybrid_property
def employee_count(self):
return len(self.employees)
@employee_count.expression
def employee_count(cls):
return (
select([func.count(Employee.id)])
.where(Employee.department_id == cls.id)
.correlate_except(Employee))
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没有运气:
Department.query.options(joinedload('employee_count')).all()
# AttributeError: 'Select' object has no attribute 'property'
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我知道我可以在查询中查询计数作为一个单独的实体,但我真的更喜欢将它作为模型的属性.这在SQLAlchemy中甚至可能吗?
编辑:为了澄清,我想避免N + 1问题并将员工数量加载到与部门相同的查询中,而不是在每个部门的单独查询中.
您尝试的加载策略是针对关系的。a 的加载column_property以与普通列相同的方式改变,请参阅延迟列加载。
employee_count默认情况下,您可以通过传递deferred=True到来推迟加载column_property。当一个列被延迟时,当访问该属性时会发出一个 select 语句。
defer而undefer从sqlalchemy.orm让这种构造查询时,可以更改:
from sqlalchemy.orm import undefer
Department.query.options(undefer('employee_count')).all()
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