Nokogiri XML解析与Rails

Question

我看了很多,但这个似乎让我在哪里

调节器

  def index
      require 'nokogiri'
      doc = Nokogiri::XML(open("http://sports.yahoo.com/top/rss.xml"))

      @links = doc.xpath('//item').map do |i|
      {'title' => i.xpath('title'), 'link' => i.xpath('link'), 'description' => i.xpath('description')}
      end
  end

视图

<ul>
  <%= debug @links.each.first %>
</ul>

调试输出

{"title"=>[#<Nokogiri::XML::Element:0x8199ce34 name="title" children=[#<Nokogiri::XML::Text:0x8199c6f0 "Kolb to get start for Eagles vs. Falcons (AP)">]>], "description"=>[#<Nokogiri::XML::Element:0x8199b660 name="description" children=[#<Nokogiri::XML::Text:0x8199a594 "Kevin Kolb will make his second straight start in place of the injured Michael Vick when the Philadelphia Eagles host Atlanta on Sunday. Eagles coach Andy Reid says Vick practiced Friday for the first time since sustaining a rib cartilage injury on Oct. 3. There's a chance Vick will be the backup quarterback against his former team.">]>], "link"=>[#<Nokogiri::XML::Element:0x81999f40 name="link" children=[#<Nokogiri::XML::Text:0x81999b58 "http://us.rd.yahoo.com/sports/rss/top/SIG=11npql9k5/*http%3A//sports.yahoo.com/nfl/news?slug=ap-eagles-qbs">]>]}

我需要的是循环链接数组并使用标题和链接访问哈希,但我不知道如何做到这一点.

Answer 1

如果我理解正确,你只需要从xpath节点获取内部文本.

{'title' => i.xpath('title').inner_text,
 'link' => i.xpath('link').inner_text, 
 'description' => i.xpath('description').inner_text 
}

.......