目前,我正在SpreadsheetDocument通过传递MemoryStream参数来创建一个包含Open XML 类的新Excel文档.我现在需要在这个SpreadsheetDocument对象上设置一个密码,但我尝试过的东西似乎不起作用.Excel文档无需输入密码即可打开.以下是我到目前为止所尝试的(mem作为MemoryStream参数):
using (SpreadsheetDocument spreadsheet = SpreadsheetDocument.Open(mem, true))
{
foreach (var sheet in spreadsheet.WorkbookPart.WorksheetParts)
{
sheet.Worksheet.Append(new SheetProtection() { Password = "test" });
}
}
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我也试过以下但没有成功:
using (SpreadsheetDocument spreadsheet = SpreadsheetDocument.Open(mem, true))
{
spreadsheet.WorkbookPart.Workbook.WorkbookProtection = new WorkbookProtection
{
LockStructure = true,
LockWindows = true,
WorkbookPassword = "test"
}
}
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我错过了什么?
小智 7
Openxml 表保护密码的输入数据类型为“HexBinaryValue”。所以输入密码要从字符串转换为十六进制二进制。
foreach (var worksheetPart in spreadsheet.WorkbookPart.WorksheetParts)
{
//Call the method to convert the Password string "MyPasswordfor sheet" to hexbinary type
string hexConvertedPassword = HexPasswordConversion("MyPasswordfor sheet");
//passing the Converted password to sheet protection
SheetProtection sheetProt = new SheetProtection() { Sheet = true, Objects = true, Scenarios = true, Password = hexConvertedPassword };
worksheetPart.Worksheet.InsertAfter(sheetProt,worksheetPart.Worksheet.Descendants<SheetData>().LastOrDefault());
worksheetPart.Worksheet.Save();
}
/* This method will convert the string password to hexabinary value */
protected string HexPasswordConversion(string password)
{
byte[] passwordCharacters = System.Text.Encoding.ASCII.GetBytes(password);
int hash = 0;
if (passwordCharacters.Length > 0)
{
int charIndex = passwordCharacters.Length;
while (charIndex-- > 0)
{
hash = ((hash >> 14) & 0x01) | ((hash << 1) & 0x7fff);
hash ^= passwordCharacters[charIndex];
}
// Main difference from spec, also hash with charcount
hash = ((hash >> 14) & 0x01) | ((hash << 1) & 0x7fff);
hash ^= passwordCharacters.Length;
hash ^= (0x8000 | ('N' << 8) | 'K');
}
return Convert.ToString(hash, 16).ToUpperInvariant();
}
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好吧,这并不完全是我想要做的,但我最终放弃了 Open XML SDK 并使用 Office.Interop 程序集来保护文档。最初使用 Open XML 的原因是因为 Interop 工作簿似乎无法使用流打开,它需要一个实际的文件。
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