Tru*_*an1 3 json dictionary swift swift2
我有一系列字典,我想转换为JSON.我的对象是类型,[[String: AnyObject]]
并希望最终得到这样的示例:
[
{ "abc": 123, "def": "ggg", "xyz": true },
{ "abc": 456, "def": "hhh", "xyz": false },
{ "abc": 789, "def": "jjj", "xyz": true }
]
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这是我正在尝试的,但编译器不喜欢我的声明:
extension Array where Element == Dictionary<String, AnyObject> {
var json: String {
do { return try? NSJSONSerialization.dataWithJSONObject(self, options: []) ?? "[]" }
catch { return "[]" }
}
}
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我怎样才能做到这一点?
斯威夫特 4:
extension Collection where Iterator.Element == [String:AnyObject] {
func toJSONString(options: JSONSerialization.WritingOptions = .prettyPrinted) -> String {
if let arr = self as? [[String:AnyObject]],
let dat = try? JSONSerialization.data(withJSONObject: arr, options: options),
let str = String(data: dat, encoding: String.Encoding.utf8) {
return str
}
return "[]"
}
}
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用法:
let arrayOfDictionaries = [
{ "abc": 123, "def": "ggg", "xyz": true },
{ "abc": 456, "def": "hhh", "xyz": false },
{ "abc": 789, "def": "jjj", "xyz": true }
]
print(arrayOfDictionaries.toJSONString())
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实现这一目标的一种简单方法是只扩展CollectionType.
使用可选的绑定和向下转换,然后序列化为数据,然后转换为字符串.
extension CollectionType where Generator.Element == [String:AnyObject] {
func toJSONString(options: NSJSONWritingOptions = .PrettyPrinted) -> String {
if let arr = self as? [[String:AnyObject]],
let dat = try? NSJSONSerialization.dataWithJSONObject(arr, options: options),
let str = String(data: dat, encoding: NSUTF8StringEncoding) {
return str
}
return "[]"
}
}
let arrayOfDictionaries: [[String:AnyObject]] = [
["abc":123, "def": "ggg", "xyz": true],
["abc":456, "def": "hhh", "xyz": false]
]
print(arrayOfDictionaries.toJSONString())
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输出:
[
{
"abc" : 123,
"def" : "ggg",
"xyz" : true
},
{
"abc" : 456,
"def" : "hhh",
"xyz" : false
}
]
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