如何在theano上实现加权二元交叉熵?

Ken*_*han 8 python theano keras lasagne cross-entropy

如何在theano上实现加权二元交叉熵?

我的卷积神经网络只能预测0~1(sigmoid).

我想以这种方式惩罚我的预测:

成本表

基本上,我想在模型预测为0时惩罚更多,但事实是1.

问题:如何使用theano和lasagne创建此加权二进制CrossEntropy函数?

我试过这个

prediction = lasagne.layers.get_output(model)


import theano.tensor as T
def weighted_crossentropy(predictions, targets):

    # Copy the tensor
    tgt = targets.copy("tgt")

    # Make it a vector
    # tgt = tgt.flatten()
    # tgt = tgt.reshape(3000)
    # tgt = tgt.dimshuffle(1,0)

    newshape = (T.shape(tgt)[0])
    tgt = T.reshape(tgt, newshape)

   #Process it so [index] < 0.5 = 0 , and [index] >= 0.5 = 1


    # Make it an integer.
    tgt = T.cast(tgt, 'int32')


    weights_per_label = theano.shared(lasagne.utils.floatX([0.2, 0.4]))

    weights = weights_per_label[tgt]  # returns a targets-shaped weight matrix
    loss = lasagne.objectives.aggregate(T.nnet.binary_crossentropy(predictions, tgt), weights=weights)

    return loss

loss_or_grads = weighted_crossentropy(prediction, self.target_var)
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但我得到以下错误:

TypeError:reshape中的新形状必须是向量或标量的列表/元组.转换为向量后得到Subtensor {int64} .0.


参考:https://github.com/fchollet/keras/issues/2115

参考:https://groups.google.com/forum/#!topic/theano- users/ R_Q4uG9BXp8

Ken*_*han 2

感谢千层面组的开发人员,我通过构建自己的损失函数解决了这个问题。

loss_or_grads = -(customized_rate * target_var * tensor.log(prediction) + (1.0 - target_var) * tensor.log(1.0 - prediction))

loss_or_grads = loss_or_grads.mean()
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