Ken*_*han 8 python theano keras lasagne cross-entropy
如何在theano上实现加权二元交叉熵?
我的卷积神经网络只能预测0~1(sigmoid).
我想以这种方式惩罚我的预测:
基本上,我想在模型预测为0时惩罚更多,但事实是1.
问题:如何使用theano和lasagne创建此加权二进制CrossEntropy函数?
我试过这个
prediction = lasagne.layers.get_output(model)
import theano.tensor as T
def weighted_crossentropy(predictions, targets):
# Copy the tensor
tgt = targets.copy("tgt")
# Make it a vector
# tgt = tgt.flatten()
# tgt = tgt.reshape(3000)
# tgt = tgt.dimshuffle(1,0)
newshape = (T.shape(tgt)[0])
tgt = T.reshape(tgt, newshape)
#Process it so [index] < 0.5 = 0 , and [index] >= 0.5 = 1
# Make it an integer.
tgt = T.cast(tgt, 'int32')
weights_per_label = theano.shared(lasagne.utils.floatX([0.2, 0.4]))
weights = weights_per_label[tgt] # returns a targets-shaped weight matrix
loss = lasagne.objectives.aggregate(T.nnet.binary_crossentropy(predictions, tgt), weights=weights)
return loss
loss_or_grads = weighted_crossentropy(prediction, self.target_var)
Run Code Online (Sandbox Code Playgroud)
但我得到以下错误:
TypeError:reshape中的新形状必须是向量或标量的列表/元组.转换为向量后得到Subtensor {int64} .0.
参考:https://github.com/fchollet/keras/issues/2115
参考:https://groups.google.com/forum/#!topic/theano- users/ R_Q4uG9BXp8
感谢千层面组的开发人员,我通过构建自己的损失函数解决了这个问题。
loss_or_grads = -(customized_rate * target_var * tensor.log(prediction) + (1.0 - target_var) * tensor.log(1.0 - prediction))
loss_or_grads = loss_or_grads.mean()
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1845 次 |
| 最近记录: |