C++程序指令

Question

我编写了这个程序,但是当我尝试编译它时,我遇到了语法错误.我找不到语法错误的位置.

它应该计算不同气体中的第二声音传播次数,用户给出的信息.

include <iostream>
#include <fstream>
using namespace std;

   int main()
         {
          int choice, gascount=0,i,sec;
          string gas[10],type;
          double speed[10],speedd;
          ifstream input;
   input.open("input.txt"); 
   if(input.fail())            
          cout<<"file did not open please check it\n";
          cin >> gas[gascount++];
      while(input)
          {
              input>>speed[gascount];
              input>>gas[++gascount];
          }
           while(choice!=5)  
               {cout<<"Choose gas would you like to use\n";
                cout<<"1  CarbonDioxide\n";
                cout<<"2  Air\n";
                cout<<"3  Helium\n";
                cout<<"4  Hydrogen\n";
                cout<<"5  Exit\n";  //5th cout for exiting program
                cin >>choice;

     switch(choice)    //use swich for user selection of gases 
        {case 1:    type="CarbonDioxide";
                    break;
         case 2:    type="Air";
                    break;
         case 3:    type="Helium";
                    break;
         case 4:    type="Hydrogen";
                    break;
         case 5:    system("exit");
         default:   printf("Illegal input: Try Again\n");
         }
          i=0;
          for(i=0;i<gascount;i++)            //loop for number of seconds
             if(type.compare(gas[i])==0)   //speed travel in gases
                {speedd=speed[i];
                 i=gascount+1;
                 }
      cout<<"You chose "<<type<<endl;
      cout<<"how many seconds did the sound travel? ";
      cin>>sec;
      while(sec<0||sec>30)
         {cout<<"must me between 0 and 30\n";
          cout<<"how many seconds did the sound travel? ";
          cin>>sec;
         }
          cout<<"The speed of sound through "<<type<<" is "<<speedd*sec*10.<<endl;
    }
    input.close();
    system("pause");

 return 0;

}

Answer 1

您的编译器有错误消息.您需要查看这些消息并一次修复一个如果您无法找到我们的重新发布它.