我有一个表数据如下
day group category appcount
-----------------------------------------
Fri F27-28 music 4
Fri F27-28 radio 1
Fri F27-28 show 1
Fri F27-28 video 8
Fri F29-32 music 6
Fri F29-32 radio 2
Fri F29-32 video 22
Fri M22- music 1
Fri M22- video 2
Fri M23-26 music 4
Fri M23-26 video 8
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现在,我想通过旋转类别和日期来获得结果,如下所示。
Age Group music-Fri music-Mon music-Sun music-Tue music-Sat music-Thu music-Wed radio-Fri radio-Mon radio-Sun radio-Tues radio-Sat radio-Thu radio-Wed
-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
F27-28 4 16 5 11 17 13 9 1 1 3 2 8 2
F29-32 6 2 6 4 4 4 2 5 2 3 2
F33-42 2 2 3 1 1 3
M22- 1 15 14 10 4 4
M23-26 4 7 5 2 12 14 7
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我尝试了一些查询,但无法实现对 2 列、日期和类别进行分组。抱歉,数据格式问题。请帮忙。
这是我的查询
SELECT *
FROM (
SELECT
[group],
[day],
category,
appcount as counts
FROM monthly_age_apps
) as s
PIVOT
(
SUM(counts)
FOR [category] IN (video, radio, show, music)
)AS pvt
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谢谢你,萨蒂什
我发现对许多数据透视查询使用条件聚合更简单:
select agegroup,
sum(case when category = 'music' and day = 'Fri' then appcount else 0 end) as music_fri,
sum(case when category = 'music' and day = 'Mon' then appcount else 0 end) as music_mon,
. . .
from
group by agegroup;
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